The function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
<h3>How to determine the function?</h3>
For a function to have its vertex on the y-axis, then the coordinate of the vertex must be:
(h,k) = (0,y)
A quadratic function is represented as:
f(x) = (x - h)^2 + k
So, we have:
f(x) = (x - 0)^2 + k
Evaluate
f(x) = x^2 + k
From the list of options, we have:
f(x) = (x - 2)(x + 2)
Expand
f(x) = x^2 - 4
Hence, the function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
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(i) I used distributive property to get the x’s and y’s out of parentheses. I then combined like-terms to simplify until I could do no more. That is your final answer for (i) is -3x - 12y
(ii) This one is similar to the first one, just with no parentheses. I combined like terms again until not like terms were left. Your final answer for (ii) is -3k -2 -2n
(iii) I started by dividing 15 by 3 and got 5, and because the 15 had an x to it, you get 5x. I then moved onto the next term, 9. 9 divided by 3, to get 3. Your final answer for (iii) is 5x + 3
I think hamburger and French fries
median: The number that occurs in the middle after arranging in ascending order of magnitude
;13 13
since both appeared in the middle,you add it and divide by 2
13+13/2
26/2
13
;The median is 13