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Akimi4 [234]
3 years ago
13

The equation for line j can be written as y = 2x + 8. Another line k is perpendicular

Mathematics
2 answers:
Daniel [21]3 years ago
3 0

Answer:

Solution given:

equation of line j is:

y=2x+8

comparing above equation with y=mx+c

we get

m=2

let slope of another line k be M

since lines are perpendicular

their product is -1

so

m *M=-1

2M=-1

M=-½

since it passes from (6,-6)

we have

(y-y1)=M(x-x1)

(y+6)=-½(x-6)

2y+12=-x+6

x+2y+12-6=0

<u>x</u><u>+</u><u>2</u><u>y</u><u>+</u><u>6</u><u>=</u><u>0</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>equation</u><u> </u><u>of</u><u> </u><u>line</u><u> </u><u>k</u><u>.</u>

GaryK [48]3 years ago
3 0

Answer:

\displaystyle y   =   - \frac{1}{2} x   - 3

Step-by-step explanation:

we are given that,

\displaystyle E _{ j}: y = 2x + 8

and it's perpendicular to E_k

since E_k is perpendicular to E_j the slope of the equation of k has to be -½

because we know that

\displaystyle  m_{ \text{perpendicular}} =   - \frac{1}{m}

we are also given a point where the perpendicular line passes as we got the slope and a point we can consider using <u>point</u><u>-</u><u>slope</u><u> </u> form of linear equation to figure out the perpendicular line

remember the point slope form

\displaystyle y -  y_{1} = m(x -  x_{1})

we got that, y1=-6,x1=6 and m=-½ thus,

substitute:

\displaystyle y -  ( - 6)=   - \frac{1}{2} (x -  6)

remove parentheses:

\displaystyle y   +  6=   - \frac{1}{2} (x -  6)

distribute:

\displaystyle y   +  6=   - \frac{1}{2} x  +  3

cancel 6 from both sides:

\displaystyle y   =   - \frac{1}{2} x   - 3

hence, the equation of line k is <u>y=</u><u>-</u><u>½</u><u>x</u><u>-</u><u>3</u>

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I need help with this one.
erastova [34]

Answer:

y = 3x + 5

Step-by-step explanation:

The equation in slope- intercept form is

y = mx + c

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 2, - 1) and (x₂, y₂ ) = (2, 11) ← 2 ordered pairs from the table

m = \frac{11+1}{2+2} = \frac{12}{4} = 3, thus

y = 3x + c ← is the partial equation

To find c substitute any ordered pair from the table into the partial equation

Using (2, 11 ), then

11 = 6 + c ⇒ c = 11 - 6 = 5

y = 3x + 5 ← equation of linear function

6 0
3 years ago
Meridith plays softball, she gets a hit about 35% of the time. What percent does she not get a hit?
kotykmax [81]

Answer:

Meridith doesn't get hit 65% of the time.

Step-by-step explanation:

If you take the 35% that she does get hit and subtract that from 100% then you will get 65%. (100-35=65)

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3 years ago
Solve 4^x-5 = 6 for x using the change of base formula log base b of y equals log y over log b
Ronch [10]

Answer:

4^x-5=6 gives the solution x=\frac{\log(11)}{\log(4)}.

4^{x-5}=6 gives the solution x=\frac{\log(6)}{\log(4)}+5.

Step-by-step explanation:

I will solve both interpretations.

If we assume the equation is 4^{x}-5=6, then the following is the process:

4^x-5=6

Add 5 on both sides:

4^x=6+5

Simplify:

4^x=11

Now write an equivalent logarithm form:

\log_4(11)=x

x=\log_4(11)

Now using the change of base:

x=\frac{\log(11)}{\log(4)}.

If we assume the equation is 4^{x-5}=6, then we use the following process:

4^{x-5}=6

Write an equivalent logarithm form:

\log_4(6)=x-5

x-5=\log_4(6)

Add 5 on both sides:

x=\log_4(6)+5

Use change of base formula:

x=\frac{\log(6)}{\log(4)}+5

6 0
3 years ago
At a fixed operating setting, the pressure in a line downstream of a reciprocating compressor has a mean value of 950 kPa with a
prisoha [69]

Answer:

4.75% probability that the line pressure will exceed 1000 kPa during any measurement

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 950, \sigma = 30

What is the probability that the line pressure will exceed 1000 kPa during any measurement

This is 1 subtracted by the pvalue of Z when X = 1000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1000 - 950}{30}

Z = 1.67

Z = 1.67 has a pvalue of 0.9525

1 - 0.9525 = 0.0475

4.75% probability that the line pressure will exceed 1000 kPa during any measurement

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