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Akimi4 [234]
3 years ago
13

The equation for line j can be written as y = 2x + 8. Another line k is perpendicular

Mathematics
2 answers:
Daniel [21]3 years ago
3 0

Answer:

Solution given:

equation of line j is:

y=2x+8

comparing above equation with y=mx+c

we get

m=2

let slope of another line k be M

since lines are perpendicular

their product is -1

so

m *M=-1

2M=-1

M=-½

since it passes from (6,-6)

we have

(y-y1)=M(x-x1)

(y+6)=-½(x-6)

2y+12=-x+6

x+2y+12-6=0

<u>x</u><u>+</u><u>2</u><u>y</u><u>+</u><u>6</u><u>=</u><u>0</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>equation</u><u> </u><u>of</u><u> </u><u>line</u><u> </u><u>k</u><u>.</u>

GaryK [48]3 years ago
3 0

Answer:

\displaystyle y   =   - \frac{1}{2} x   - 3

Step-by-step explanation:

we are given that,

\displaystyle E _{ j}: y = 2x + 8

and it's perpendicular to E_k

since E_k is perpendicular to E_j the slope of the equation of k has to be -½

because we know that

\displaystyle  m_{ \text{perpendicular}} =   - \frac{1}{m}

we are also given a point where the perpendicular line passes as we got the slope and a point we can consider using <u>point</u><u>-</u><u>slope</u><u> </u> form of linear equation to figure out the perpendicular line

remember the point slope form

\displaystyle y -  y_{1} = m(x -  x_{1})

we got that, y1=-6,x1=6 and m=-½ thus,

substitute:

\displaystyle y -  ( - 6)=   - \frac{1}{2} (x -  6)

remove parentheses:

\displaystyle y   +  6=   - \frac{1}{2} (x -  6)

distribute:

\displaystyle y   +  6=   - \frac{1}{2} x  +  3

cancel 6 from both sides:

\displaystyle y   =   - \frac{1}{2} x   - 3

hence, the equation of line k is <u>y=</u><u>-</u><u>½</u><u>x</u><u>-</u><u>3</u>

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