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jeka94
4 years ago
11

a recipe calls for 2/5 cup of chicken broth and 1/4 cup of vegetable broth what is the total amount of broth needed for the reci

pe
Mathematics
2 answers:
Tomtit [17]4 years ago
6 0
The total amount would be 13/20 I believe I'm not too sure
ruslelena [56]4 years ago
5 0
Hello!

2/5 = 0.4 as a decimal

1/4 = 0.25 as a decimal

0.4 + 0.25 = 0.65

0.65 = 65/100 as a fraction. This can be simplified to 13/20, if you divide by 5. 

ANSWER: 

The total amount of broth needed for the recipe is 13/20, or 0.65 cups. 
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Answer: -4/5, in decimal form -0.8

Step-by-step explanation: −4.1+2n+1+0.3n

Combine Like Terms:

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Answer:

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p_v =P(Z  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis,and we have enough evidence to conclude that the true mean is significantly lower thn 4.8 at 10% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=4.6 represent the sample mean

\sigma=0.9 represent the population standard deviation

n=180 sample size  

\mu_o =4.8 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if thetrue mean is below the specifications, the system of hypothesis would be:  

Null hypothesis:\mu \geq 4.8  

Alternative hypothesis:\mu < 4.8  

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{4.6-4.8}{\frac{0.9}{\sqrt{180}}}=-2.98    

P-value

Since is a one sided test the p value would be:  

p_v =P(Z  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis,and we have enough evidence to conclude that the true mean is significantly lower thn 4.8 at 10% of signficance.  

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