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Viefleur [7K]
3 years ago
13

The sum of two numbers is negative thirty. One number is five times the other

Mathematics
2 answers:
Mademuasel [1]3 years ago
4 0

Answer:

-25, -5

Step-by-step explanation:

Let's write a system of equations. Lets call x and y the numbers, where x is 5 times y.

x + y = -30

x = 5y

Plugging this in, we get:

5y + y = -30

y = -5

Since y = -5, we can plug this in, and see that x = -25.

vaieri [72.5K]3 years ago
3 0

Answer:

-5 & -25

Step-by-step explanation:

1st number=x

2nd number=5x

x+5x=-30

6x=-30

x=-5

5x=-25

So the numbers are -5 & -25

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Find the value of x.<br><br> X=
givi [52]

Answer:

x = 65

Step-by-step explanation:

The opposite angles of a cyclic quadrilateral sum to 180° , then

x + 115 = 180 ( subtract 115 from both sides )

x = 65

5 0
3 years ago
A scientist had 3 1/2 liters of vinegar. He poured 2/3 of the vinegar into beaker. He then used 3/5 of the vinegar in the beaker
valentinak56 [21]

Answer:

A)2100 ml

Step-by-step explanation:

Given total vinegar is 3 1/2 liters and the used vinegar is  3/5 of the vinegar in the beaker:

#First calculate the amount of vinegar not poured in the beaker:

V_o=V_t-V_b\\\\=3\frac{1}{2}(1-\frac{2}{3})\\\\=1\frac{1}{6}

#Calculate amount of vinegar used in experiment:

V_b=\frac{2}{3}V_t=\frac{2}{3}(3\frac{1}{2})=2\frac{1}{3}\\\\V_u=\frac{3}{5}V_b=\frac{3}{5}\times 2\frac{1}{3}=1\frac{2}{5}

#The unused vinegar is therefore calculated by subtracting the used vinegar from the total at the start of the experiment:

V_r=V_t-V_u\\\\=3\frac{1}{2}-1\frac{2}5}\\\\=2\frac{1}{10}\times 1000\ ml\\\\=2100\ ml

Hence, the unused vinegar is 2100 ml

8 0
3 years ago
A number, n, is multiplied by -5/8. The product is -0.4. What is the value of n?
Advocard [28]
The answer is D. 16/25

-5/8 = -0.625

-0.4 divided by -0.625 = 0.64

0.64= 16/25
5 0
3 years ago
What is the value of 1/0?
MaRussiya [10]
The correct answer is Undefined

I just did this in pre-calculus and I’m positive it is correct
4 0
2 years ago
In the last several weeks, 18 days saw rain and 29 days saw high winds. in the same time period 7 days saw both rain and high wi
liq [111]

Answer:

40 days saw either rain or high winds

Step-by-step explanation:

We solve this question using Venn sets.

I am going to say that:

Set A: Rain

Set B: High winds.

18 days saw rain

This means that A = 18

29 days saw high winds

This means that B = 29

7 days saw both rain and high winds.

This means that A \cap B = 7

How many days saw either rain or high winds?

This is

A \cup B = A + B - A \cap B

Sp

A \cup B = 18 + 29 - 7 = 40

40 days saw either rain or high winds

5 0
3 years ago
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