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3 years ago

The sum of two numbers is negative thirty. One number is five times the other

Mathematics

2 answers:

Mademuasel [1]3 years ago

4 0

Answer:

-25, -5

Step-by-step explanation:

Let's write a system of equations. Lets call x and y the numbers, where x is 5 times y.

x + y = -30

x = 5y

Plugging this in, we get:

5y + y = -30

y = -5

Since y = -5, we can plug this in, and see that x = -25.

vaieri [72.5K]3 years ago

3 0

Answer:

-5 & -25

Step-by-step explanation:

1st number=x

2nd number=5x

x+5x=-30

6x=-30

x=-5

5x=-25

So the numbers are -5 & -25

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Ber [7]

Answer:

11 months

Step-by-step explanation:

the math that i did was i kept adding 400 to 2500 and counted every four hundred that i added witch was 11 until i got to 7000 so the answer is 11 months. You will have some left over which you will have 300 left over.

8 0

3 years ago

If B is the midpoint of AC and AB = 4x + 14 and BC = x + 20, determine how long AC is.

Serhud [2]

Answer:

44 units

Step-by-step explanation:

Since B is the mid-point of AC

AB=BC

or,4x+14=x+20

or, 4x-x=20-14

or 3x=6

or,x=6/3=2

AC=AB+BC

= 4x+14+x+20

= 4(2) + 14 +2 +20

= 8+14+22

=44 units

5 0

3 years ago

Read 2 more answers

Rectangle ABCD has vertices at (-7,-2); (1, -2); (1, -8); and (-7, -8) respectively. If GHJK is a similar rectangle where G(2, 5

Gennadij [26K]

Answer:

Points J and K could be located at:

J(2,2)

K(6,2)

Step-by-step explanation:

Consider the vertices have a x and y coordinate:

A: x coordinate=-7 y coordinate=-2

B: x coordinate=1 y coordinate=-2

C: x coordinate=1 y coordinate=-8

D: x coordinate=-7 y coordinate=-8

G: x coordinate=2 y coordinate=5

H: x coordinate=6 y coordinate=5

Then it is possible to calculate the distance between the x and y coordinates:

x coordinate of Vertices AB:

x coordinate of B- x coordinate of A=1-(-7)=8

The distance between A and B is 8

y coordinate of Vertices AC:

y coordinate of A- y coordinate of C=-2-(-8)=6

The distance between A and C is 6

Then we know that the side AB of Rectangle ABCD measures 8 and the side AC, measures 6.

Repeat the analysis with Rectangle GHJK. In this case, is only possible to calculate the distance with x coordinate.

x coordinate of Vertices GH:

x coordinate of H- x coordinate of G=6-(2)=4

The distance between G and H is 4

We can see that the distance in x of the Rectangle ABCD is 8, and the distance in x of the Rectangle GHJK is 4, it means that the measure of ABCD is twice GHJK.

Then, if the distance in y coordinate of Vertices AC is 6, we could say that the distance in y coordinate of Vertices GJ is 3.

Points J and K could be located at:

J(2,2)

K(6,2)

3 0

3 years ago

Write an equation of a line parallel to line EF below in slope-intercept form that passes through the point (2, 6).

N76 [4]

Answer:

y = -⅔x + ²²/₃

Step-by-step explanation:

1. Calculate the slope of EF

Assume E is at (-2, 5) and F is at (1, 3).

m₁ = (y₂ - y₁)/(x₂ - x₁) = (3 - 5)/(1 -(-2)) = -⅔

2. Calculate the slope of the parallel line

m₂ = m₁ = -⅔

3. Calculate its y-intercept

y = mx + b

6 =-⅔(2) + b

Simplify

6 = -⁴/₃ + b

Add ⁴/₃ to each side

b = 6 + ⁴/₃ = ¹⁸/₃ + ⁴/₃ = ²²/₃

The y-intercept is at (0,²²/₃).

4. Write the equation for the line

y = -⅔x + ²²/₃

The diagram shows EF in red. The parallel line in black passes through (2, 6) with a y-intercept at (0,²²/₃).

7 0

4 years ago

Use the scale factor to find the area of the enlarged figure. Explain your steps.

lora16 [44]

Answer:

12.8 units

Step-by-step explanation:

25.6/8 = a/4

a = 4 × 25.6/8

a = 12.8

3 0

3 years ago

Read 2 more answers