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liubo4ka [24]
3 years ago
8

Someone help please, use a variable equation to represent the situation and solve it using inverse operations.

Mathematics
1 answer:
DanielleElmas [232]3 years ago
5 0

ANSWER:

Let no of rides be x.

So, According to question

2.5x + 5 = 50

2.5(x + 2) = 50

x + 2 = 50/2.5

x + 2 = 20

x = 18 rides.

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Y = −2 4x − 3y = 18 solved by substitution please show work so i can understand :)
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Answer:

Step-by-step explanation:

y = -2

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4x - 3(-2) = 18

4x + 6 = 18

4x = 12

x = 3

(3, -2)

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3 years ago
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The point C(-2, -4) is rotated 270° clockwise around the origin. What are the coordinates of the resulting point, C′?
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(2,4)

Step-by-step explanation:

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joanna split three pitchers of water equally among her eight plants.what fraction of a pitcher did each plant get?
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3/8 of a fraction is the amount of water that was split 

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To find the measure of ∠A in ∆ABC, use the___(Pythagorean Theorem, Law of Sines, Law of Cosines). To find the length of side HI
nadya68 [22]

<u>Part 1) </u>To find the measure of ∠A in ∆ABC, use

we know that

In the triangle ABC

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\frac{a}{sin\ A}=\frac{b}{sin\ B}=\frac{c}{sin\ C}

in this problem we have

\frac{a}{sin\ A}=\frac{b}{sin\ theta}\\ \\a*sin\ theta=b*sin\ A\\ \\ sin\ A=\frac{a*sin\ theta}{b} \\ \\ A=arc\ sin (\frac{a*sin\ theta}{b})

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<u>the answer  Part 1) is</u>

Law of Sines

<u>Part 2) </u>To find the length of side HI in ∆HIG, use

we know that

In the triangle HIG

Applying the law of cosines

g^{2}=h^{2}+i^{2}-2*h*i*cos\ G

In this problem we have

g=HI

G=angle Beta

substitute

HI^{2}=h^{2}+i^{2}-2*h*i*cos\ Beta

HI=\sqrt{h^{2}+i^{2}-2*h*i*cos\ Beta}

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Law of Cosines

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3 years ago
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Order from least to greatest
Dafna1 [17]
3.75, 3.9, 4.256, 4.258, 4.5
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