Answer:
Extraneous Solutions An extraneous solution is a root of a transformed equation that is not a root of the original equation because it was excluded from the domain of the original equation. Example 1: Solve for x, 1 x − 2 + 1 x + 2 = 4 (x − 2) (x + 2).
<span>y − 1 = 4(x + 3)
y - 1 = 4x + 12
y = 4x + 13, slope = 4
parallel lines, slope is the same so slope = 4
</span><span>passes through the point (4, 32)
</span>y = mx+b
b = y - mx
b = 32 - 4(4)
b = 32 - 16
b = 16
equation
y = 4x + 16
For this case we have:
Be a function of the form 
Where:
If we want to find f (-2), we substitute 
, then:
Since we have a negative root, the result will be given by complex numbers. By definition:
So:
Answer:
Answer:
here
Step-by-step explanation:
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Answer:
The angles are 79.45, 59.02 and 41.53 degrees to the nearest hundredth.
Step-by-step explanation:
We have a triangle with sides of length 8.6, 5.8 and 7.5 feet.
Using the Cosine Rule to find the measure of the angle opposite the side of length 8.6 feet:
cos X = (8.6^2 - 5.8^2 - 7.5^2) / ( -2*5.8*7.5)
= 0.18310
X = 79.45 degrees.
We can now find another angle using the sine rule:
8.6 / sin 79.45 = 7.5/ sin Y
sin Y = (7.5 * sin 79.45) / 8.6
Y = 59.02 degrees
So the third angle = 180 - 79.45 - 59.02
= 41.53 degrees.
