Answer:
I think its C if I'm wrong, sorrryyy
Answer: Your answer would be 6
Step-by-step explanation:
Factored Form:
x^2 - 4x - 5
Simplifying:
x^2 + - 4x + - 5 = 0
Reorder the terms:
- 5 + - 4x + x^2 = 0
Solving for variable " x":
Subproblem 1:
Set the factor ( - 1 + - 1x) equal to Zero and attempt to solve.
Simplifying:
- 1 + - 1x = 0
Solving:
- 1 + - 1x = 0
Move all terms containing x to the left, all other terms to the right
Add 1 to each side of equation:
- 1 + 1 + - 1x = 0 + 1
Combine Like Terms: 0 + 1 = 1
x = - 1
Divide each side by - 1
x = - 1
Simplifying: x = - 1
Subproblem 2: Set the factor (5 + - 1x) equal to Zero attempt to solve
Simplifying:
5 + - 1x = 0
Move all terms containing x to the left, all other terms to the right
Add - 5 to each side of the equation
5 + - 5 + - 1x = 0 + 5
Combine Like terms: 5 + - 5 = 0
0 + - 1x = 0 + - 5
- 1x = 0 + - 5
Combine Like Terms: 0 + - 5 = - 5
- 1x = - 5
Divide each side by - 1
x = 5
Simplifying:
x = 5
Solution:
x = { - 1, 5}
Answer when factored:
(x + 1)(x - 5)
hope that helps!!!
Using sampling concepts, it is found that this is an example of independent samples.
- For dependent samples, there is a paired measurement for one set of items.
- For independent samples, separate measurements are made on two different sets, that is, the value on one sample reveal no information about the values on the other sample.
In this problem, there are two samples, the sample composed of male workers and the one composed of female workers, and separate measurements are taken, hence, it is an independent sample.
A similar problem is given at brainly.com/question/23106151
You can solve for the velocity and position functions by integrating using the fundamental theorem of calculus:
<em>a(t)</em> = 40 ft/s²
<em>v(t)</em> = <em>v </em>(0) + ∫₀ᵗ <em>a(u)</em> d<em>u</em>
<em>v(t)</em> = -20 ft/s + ∫₀ᵗ (40 ft/s²) d<em>u</em>
<em>v(t)</em> = -20 ft/s + (40 ft/s²) <em>t</em>
<em />
<em>s(t)</em> = <em>s </em>(0) + ∫₀ᵗ <em>v(u)</em> d<em>u</em>
<em>s(t)</em> = 10 ft + ∫₀ᵗ (-20 ft/s + (40 ft/s²) <em>u</em> ) d<em>u</em>
<em>s(t)</em> = 10 ft + (-20 ft/s) <em>t</em> + 1/2 (40 ft/s²) <em>t</em> ²
<em>s(t)</em> = 10 ft - (20 ft/s) <em>t</em> + (20 ft/s²) <em>t</em> ²
