The answer to the question is A.
Answer:
They move at 2.8 m/s and in the opposite direction.
Explanation:
Answer:
112 m/s², 79.1°
Explanation:
In the x direction, given:
x₀ = 0 m
x = 19,500 cos 32.0° m
v₀ = 1810 cos 20.0° m/s
t = 9.20 s
Find: a
x = x₀ + v₀ t + ½ at²
19,500 cos 32.0° = 0 + (1810 cos 20.0°) (9.20) + ½ a (9.20)²
a = 21.01 m/s²
In the y direction, given:
y₀ = 0 m
y = 19,500 sin 32.0° m
v₀ = 1810 sin 20.0° m/s
t = 9.20 s
Find: a
y = y₀ + v₀ t + ½ at²
19,500 sin 32.0° = 0 + (1810 sin 20.0°) (9.20) + ½ a (9.20)²
a = 109.6 m/s²
The magnitude of the acceleration is:
a² = ax² + ay²
a² = (21.01)² + (109.6)²
a = 112 m/s²
And the direction is:
θ = atan(ay / ax)
θ = atan(109.6 / 21.01)
θ = 79.1°
Answer:
The Questions are
a. Calculate the x-component of the electric field, in newtons per coulomb
b. Calculate the y-component of the electric field, in newtons per coulomb
c. Calculate the z-component of the electric field, in newtons per coulomb
d. Calculate the magnitude of the electric field, in newtons per coulomb.
Explanation:
Given that,
Φx= 85 N•m2/C. X direction
Φy= -85 N•m2/C. Y direction
Φz = 0. Z direction
Radius of loop =3cm=0.03m
Surface area of the circle is πr²
A=22/7×0.03²
A=0.00283m²
Flux is given as Φ=EA
a. Φx=ExA
Ex=Φx/A
Ex=85/0.00283
Ex=30035.33N/C
b. Ey=Φy/A
Ey=-85/0.00283
Ey=-30035.33N/C.
c. Ez=Φz/A
Ez, =0/A
Ez=0N/C
d. Magnitude of E.
E=√Ex²+Ey²+Ez²
E=√(30035.33)²+(-30035.33)²
E=42476.38N/C.