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gizmo_the_mogwai [7]
3 years ago
12

How would an object need to move in order for total distance traveled and displacement to be equal?

Physics
1 answer:
mart [117]3 years ago
6 0

An object need to move in a straight line in the same direction in equal intervals of time in order for total distance traveled and displacement to be equal.

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The speed of propagation of seismic waves is about 4km/s an earthquake takes place in Turkey at 13:21:00 the center of the earth
dybincka [34]

Answer:

14:30:00

Explanation:

because the speed of propagation of seismic waves is at 500

7 0
3 years ago
What is gravity?what is one solar day?<br>​
mafiozo [28]

Answer:

<h2>Gravity :</h2><h3>the force that attracts a body towards the centre of the earth, or towards any other physical body having mass.</h3>

<h2>Solar day</h2><h3>A solar day is the time it takes for the Earth to rotate about its axis so that the Sun appears in the same position in the sky.</h3><h2> or</h2><h3>It is the time between successive meridian transits of the sun at a particular place.</h3>
6 0
3 years ago
A car has a mass of 1200 kg and a velocity of 14 m/s. Calculate the<br> momentum of the car.
worty [1.4K]

Answer:

p = 16,800

Explanation:

5 0
3 years ago
A block is given an initial velocity of 3.00 m/s up a frictionless incline of angle 20 degrees. How far up the incline does the
daser333 [38]

Answer:

The distance moved by the block is 1.34 m

Explanation:

Given;

initial velocity of the block, u = 3 m/s

angle of inclination, θ = 20⁰

The net horizontal force acting on the block;

∑Fx = - mgsinθ

Apply Newton's second law of motion, to determine the constant acceleration of the block.

∑Fx = ma

- mgsinθ = ma

-gsinθ = a

Apply the following Kinematic equation, to determine how far up, the block moved before coming to rest.

V_f^2 = V_i^2 + 2a(x_f -x_i)\\\\0 = V_i^2 + 2[-gsin  \theta(x_f-0)]\\\\0 = V_i^2  - 2gsin \theta(x_f)\\\\ 2gsin \theta(x_f) = V_i^2\\\\x_f = \frac{V_i^2}{2gsin \theta} = \frac{(3)^2}{2 \ \times \ 9.8 \ \times \ sin(20)} = 1.34 \ m

Therefore, the distance moved by the block is 1.34 m

6 0
3 years ago
You are in a hot air balloon (yes, another balloon problem!) rising from the ground at a constant velocity of 2.00 m/s upward. t
Daniel [21]
If all you need is the initial speed of the cork, you can solve this using only two of your given:
2.00 m.s upward and 6.60 m.s horizontally.

If you take in consideration the movement of the cork, you know that it was both going up and forward at the same time, this means that it was moving at a diagonal direction. Now you can solve this by using the Pythagorean theorem where: 

c =  \sqrt{ a^{2} +  b^{2}  }

Why? Because the vertical and the horizontal motion creates a movement that is diagonal, which when put in a free-body diagram, creates a right triangle. 

Going back to your problem, when applying this, the diagonal of a right triangle is the hypotenuse, so this is what you are looking for. The horizontal and vertical motion will represent the other 2 sides of the triangle. 

Now let's put that into your formula:

c = \sqrt{ a^{2} + b^{2} }

Vi = \sqrt{ Vx^{2} + Vy^{2} }

Where: Vx is your horizontal velocity
             Vy is your vertical velocity
             Vi  is your initial velocity

Now let's put in your given:

Vi = \sqrt{ Vx^{2} + Vy^{2} }
Vi = \sqrt{ 6.60^2} + 2.00^{2} }
Vi = \sqrt{ 43.56 + 4.00 }
Vi = \sqrt{ 47.56 }
Vi = 6.8964 m/s

So your initial velocity is 6.8964 m/s or 6.90 m/s
5 0
4 years ago
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