What is the gravitational potential energy of a 63.5kg skateboarder at the top of a 0.61m high ramp

Physics

1 answer:

Lady bird [3.3K]4 years ago

4 0

Answer:

1.1 m/s

Explanation:

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A particle of mass 10 g and charge 80 mC moves through a uniform magnetic ﬁeld,in a region where the free-fall acceleration is .

Alex777 [14]

Answer:

$B=1.223\frac{T\cdot m}{s}\frac{1}{v}$

Explanation:

According to the first Newton's law, when a particle moves with constant velocity, the sum of forces on it is zero. So, we have:

$F_m=F_g$

Here $F_m=qvBsin\theta$ is the magnetic force and $F_g=mg$ is the gravitational force. The velocity of the particle is perpendicular to the magnetic field, so $\theta=90^\circ$ . Replacing and solving for B:

$qvBsin(90^\circ)=mg\\B=\frac{mg}{qv}\\B=\frac{mg}{q}\frac{1}{v}\\B=\frac{(10*10^{-3}kg)(9.8\frac{m}{s^2})}{80*10^{-3}C}\frac{1}{v}\\B=1.223\frac{T\cdot m}{s}\frac{1}{v}$

4 0

3 years ago

WILL MARK BRAINLIEST!

viva [34]

Answer:

True

Explanation:

Newton's first law of motion states that an object at rest will stay at rest unless acted upon by an outside force.

5 0

3 years ago

Read 2 more answers

Two small insulating spheres with radius 3.50×10−2 m are separated by a large center-to-center distance of 0.555 m. One sphere i

xz_007 [3.2K]

Answer:

$E = 7.83 \times 10^5 N/C$

Explanation:

Since we know that two sphere is oppositely charged so net electric field at the mid point of two balls will be sum of the electric field due to each ball at the mid point

So we know that

$E = \frac{kq_1}{r^2} + \frac{kq_2}{r^2}$