Graph of f(x-3) is compressed by a factor of
horizontally of f(x).
<u>Step-by-step explanation:</u>
We have, the graph of f(x)=
, on replacing f(x) by f(x-3) we get:
=
.Below shown are the images for graph of f(x) and f(x-3). Both are functions are exponential , and so having exponential graph but f(x-3) is compressed by a factor of
horizontally . Domain and range of both functions are same i.e. F(x) & f(x-3) domain & range are same , just difference in graph :
.
Answer:

Step-by-step explanation:

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>you</em>
<em>let</em><em> </em><em>me</em><em> </em><em>know</em><em> </em><em>if</em><em> </em><em>you</em><em> </em><em>have</em><em> </em><em>another</em><em> </em><em>questions</em><em>:-)</em>
Answer:
OPTION B
Step-by-step explanation:
<h2>
3a - 5</h2>
3 and 'a' are multiplied and 5 is subtracted from the result.
OPTION B says 5 less than 3 times a number would fit perfectly.
Other options talk about adding or taking ratios and clearly do not fit the case.
Hence, the right answer is Option B.
Answer: Distance between line and point =
4√5 -3/2√10
Step-by-step explanation:
Distance between the line is
= √ ((9-0)²+(0+1)²)
= √ (89+1)
= √90
= 3√10
Half of the line = 3/2√10
Distance of one side of the line and the point.
= √((9-1)²+(0-4)²)
= √((8)²+(-4)²)
=√64+16
= √80
= 4√5
Distance between line and point =
4√5 -3/2√10