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Olegator [25]
3 years ago
15

What value of x is in the solution set of 4х – 12 < 16 + 8x

Mathematics
1 answer:
ddd [48]3 years ago
6 0

Answer:

Step-by-step explanation:

4x - 12 < 16 + 8x

-12 - 16 < 8x - 4x

-28 < 4x

-7 < 4x

-7/4 < x or x > -7/4........so anything greater then -7/4 (or - 1 3/4) is in ur solution set

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The Ellipse equation is:   \dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=1       where

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4 years ago
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