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Llana [10]
3 years ago
13

Stans steak house has a server to cook ratio of 5 to 2.The total number of servers and cooks is 42. How many servers does Stans

steakhouse employ?
Mathematics
1 answer:
aivan3 [116]3 years ago
3 0

Answer: 30 servers

5+2 = 7

42/7 = 6 sets of employees

5*6 = 30 servers

Step-by-step explanation:

5+2 = 7

42/7 = 6 sets of employees

5*6 = 30 servers

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V(t) = 1 + 2sin(t^2/2) solve for t
Crank

Answer:

omg i'm so sorry thats the wronge answer i ment this to go to a diffrent question

Step-by-step explanation:


7 0
3 years ago
A city manage must predict the population of the city between the years 2000
bezimeni [28]

Answer:

the answer to predict the city's population is 2050

7 0
3 years ago
What is 8 × 1 + 3 × 0.1 + 9 × 0.01 in standard form
emmasim [6.3K]

Answer:

0.216

Step-by-step explanation:

8 \times 1 \times 3 \times 0.1 \times 9 \times 0.01\\\\=(8\times1)(3\times0.1)(9\times0.01)\\\\=8(0.3)(0.09)\\\\=(8\times0.3)(0.09)\\\\=(2.4)(0.09)\\\\=2.4\times0.09\\\\=0.216

is this the standard form?

5 0
3 years ago
In the diagram, the length of segment QV is 15 units. What is the length of segment TQ?
GrogVix [38]

Answer:

14 units is the answer

Step-by-step explanation:

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5 0
3 years ago
WILL mark brainliest!
Angelina_Jolie [31]

Answer:

  110.5348 minutes

Step-by-step explanation:

The difference from room temperature changes from 103 to 59 in 46 minutes, so that difference can be modeled by the exponential equation ...

  Δt = 103×(59/103)^(t/46)

We want to find t for the temperature difference Δt = 91 -64 = 27.

  27 = 103×(59/103)^(t/46)

  27/103 = (59/103)^(t/46) . . . . . divide by 103

Taking logs gives the linear equation ...

  log(27/103) = (t/46)log(59/103)

Multiplying by the inverse of the coefficient of t, we get ...

  t = 46·log(27/103)/log(59/103) ≈ 46·(-0.58147346)/(-0.24198521)

  ≈ 110.5347

It will take about 110.5347 minutes for the turkey to cool to 91 °F internally.

_____

<em>Comment on 4 decimal places</em>

An answer correct to 4 decimal places (7 significant digits) is a pretty good indication that the problem was worked correctly. However, that level of precision in the timing makes little sense in this context. Most thermometers will take at least a few seconds to register the temperature to within a tenth of a degree or so. This problem is asking for an answer that is within 6 milliseconds and 30 micro-degrees. Neither of these is anywhere near realistic for a kitchen meat thermometer.

More realistic would be an answer to 4 <em>significant figures</em>, a tenth of a minute and a few hundredths of a degree.

(The rate of change at the time of interest is about -0.33 degrees per minute.)

6 0
3 years ago
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