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erastova [34]
3 years ago
5

What is the following sum? 2(^3√16x^3y)+4(^3√54x^6y^5)

Mathematics
2 answers:
victus00 [196]3 years ago
6 0
Option A: 4x(^3√2y)+12x^2y(^3√2y^2)
Sever21 [200]3 years ago
3 0

Answer: the answer is a

Step-by-step explanation:

I just took the test

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Anderson won $10000 in a Lotto competition.
kozerog [31]

Answer:

jimmy got 30,000

Step-by-step explanation:

10,000

the wife got 60% = 60,000

jimmy got 3x prince = 30,000

prince = 10,000

8 0
3 years ago
Find the difference in simplest form:
Andrew [12]

Answer:

D. is the answer I got i think it is right but IDK

4 0
3 years ago
Read 2 more answers
What is 20% of 180<br>please i realy need to answer this​
blagie [28]

Answer:

36

20 percent * 180 =

(20:100)* 180 =

(20* 180):100 =

3600:100 = 36

Now we have: 20 percent of 180 = 36

Question: What is 20 percent of 180?

Percentage solution with steps:

Step 1: Our output value is 180.

Step 2: We represent the unknown value with $x$.

Step 3: From step 1 above,$180=100\%$.

Step 4: Similarly, $x=20\%$.

Step 5: This results in a pair of simple equations:

$180=100\%(1)$.

$x=20\%(2)$.

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

$\frac{180}{x}=\frac{100\%}{20\%}$

Step 7: Again, the reciprocal of both sides gives

Step-by-step explanation:

Hope it is helpful.....

3 0
3 years ago
An adult ticket to a museum costs 3$ more than a children’s ticket. When 200 adult tickets and 100 children tickets are sold, th
antiseptic1488 [7]

The cost of children’s ticket is $ 5

<h3><u>Solution:</u></h3>

Let "c" be the cost of one children ticket

Let "a" be the cost of one adult ticket

Given that adult ticket to a museum costs 3$ more than a children’s ticket

<em>Cost of one adult ticket = 3 + cost of one children ticket</em>

a = 3 + c  ------ eqn 1

<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>

200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100

200 \times a + 100 \times c = 2100

200a + 100c = 2100 ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>

Substitute eqn 1 in eqn 2

200(3 + c) + 100c = 2100

600 + 200c + 100c = 2100

600 + 300c = 2100

300c = 1500

<h3>c = 5</h3>

Thus the cost of children’s ticket is $ 5

6 0
3 years ago
Add the polynomials <br><br> 3x^5-2x^3+4x<br> + 4x^6-5x^5+4x^3-x^2
RUDIKE [14]

Answer: B

4x^{6} - 2x^{5} + 4x^{3} -x^{2} +4x

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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