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erastova [34]
3 years ago
5

What is the following sum? 2(^3√16x^3y)+4(^3√54x^6y^5)

Mathematics
2 answers:
victus00 [196]3 years ago
6 0
Option A: 4x(^3√2y)+12x^2y(^3√2y^2)
Sever21 [200]3 years ago
3 0

Answer: the answer is a

Step-by-step explanation:

I just took the test

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Given the function (x) - 9x+8, evaluate w(5).
Maru [420]
W(5)
5-9*5+8
5-45+8=-32
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3 years ago
What is m∠B?<br><br>A.51<br><br>B..129<br><br>C.134<br><br>D.141
san4es73 [151]

Answer:

I think it 129 If not try 4

7 0
3 years ago
A heap of grain is shaped as a cone ADCF with height 5 m and base radius 2 m, as shown on the diagram. A and C are points on the
hoa [83]

Answer:

The angle between [A_F] and the base of the cone = 68.2°

The area of the base of the cone ≈ 12.57 m²

Step-by-step explanation:

The given parameters are;

The height of the cone = 5 m

The base radius of the cone  = 2 m

The angle which the A\hat OC = 120°

Therefore, we have;

The angle between [A_F] and the base of the cone = The angle between [CF]  and the base of the cone

The angle between [CF]  and the base of the cone = tan⁻¹(5/2) = tan⁻¹(2.5) ≈ 68.2°  

∴ The angle between [A_F] and the base of the cone = The angle between [CF]  and the base of the cone = 68.2°

The angle between [A_F] and the base of the cone = 68.2°

The area of the base of the cone = π × r² = π × 2² = 4·π ≈ 12.57

The area of the base of the cone ≈ 12.57 m².

8 0
3 years ago
Given f(x) = 15x + 35, what is the domain of f?
xeze [42]
All real values of x
5 0
4 years ago
Read 2 more answers
An account grows at an annual interest rate of r⁡​ ⁣, so it grows by a factor of x=1+r⁡​ ⁣⁣ ​⁡ each year. The function A(x)=800x
Paladinen [302]

Given:

Annual interest rate = r⁡​%

Growth factor : x = 1 + r⁡​

The below function gives the amount in the account after 4 years when the growth factor is x⁡​ ⁣⁣.

A(x)=800x^4+350x^3+500x^2+600x

To find:

The total amount in the account if the interest rate for the account is 3% each year and initial amount.

Solution:

Rate of interest = 3% = 0.03

Growth factor : x = 1 + ⁡0.03 = 1.03

We have,

A(x)=800x^4+350x^3+500x^2+600x

Substitute x=1.03 in the given function, to find the total amount in the account if the interest rate for the account is 3% each year.

A(1.03)=800(1.03)^4+350(1.03)^3+500(1.03)^2+600(1.03)

A(1.03)=800(1.12550881)+350(1.092727)+500(1.0609&#10;)+618

A(1.03)=900.407048+382.45445+530.45+618

A(1.03)=2431.311498&#10;

A(1.03)\approx 2431.31&#10;

Therefore, the total amount in the account is 2431.31 if the interest rate for the account is 3% each year.

For initial amount the rate of interest is 0.

Growth factor : x = 1 + ⁡0 = 1

Substitute x=0 in the given function to find the initial amount.

A(1)=800(1)^4+350(1)^3+500(1)^2+600(1)

A(1)=800+350+500+600

A(1)=2250

Therefore, 2250 was put into the account at the beginning.

3 0
3 years ago
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