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galina1969 [7]
3 years ago
14

Which portion of the cerebral cortex is most closely adjacent to the ears?

Biology
1 answer:
ikadub [295]3 years ago
3 0
<span>The temporal lobes is a portion of the cerebral cortex that is most closely adjacent to the ears. Its function is a responsible for processing auditory information from the ears (hearing). It is mainly revolves around hearing and selective listening and receives sensory information such as sounds and speech from the ears. Furthermore, it is also a key to being able to comprehend or understand meaningful speech. Thus, we would not be able to understand someone talking to us if it wasn’t for the temporal lobe. Lastly, this love is special because it makes sense of all different sounds and pitches that is being transmitted from the sensory receptors of the ears. </span>
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A sitz bath method of bathing is most appropriate for this client .

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3 years ago
What term is used to describe the nuclear contents during interphase
kolezko [41]

Chromatin is the component that specifies the nuclear contents during inter-phase.

<u>EXPLANATION:</u>

  • The term inter-phase is the type of phase in which the cells would exhibit in all parts of its life.
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8 0
3 years ago
3. In a field of sugar beets in Georgia the net primary productivity is 120 grams/m^2/day, and the
konstantin123 [22]

Answer and Explanation:

Available Data:

  • 1 gr beets = 2,000 cal
  • NPP = GPP – Respiration = 120 grams/m2/day
  • NPP= Net primary productivity of a system
  • GPP= Gross productivity of the producers
  • Respiration loss 25% of NPP
  • Insolation energy is 800 calories/cm2/day
  • % Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

1) Find the gross productivity of the sugar beets.

We need to calculate the GPP, which equals NPP - Respiration rate. The respiration loss is 25% of the NPP. This is:

100% NPP--------------- 120 g/m²/day

25% NPP ----------------X = (25 x 120)/100 = 30 g/m²/day

Now that we know the values of NPP and respiration rate, we can calculate the GPP.

GPP = NPP - Respiration

GPP = 120 (g/m²/day) - 30 (g/m²/day)

GPP = 90 g/m²/day

GPP = 0.009 g/cm²/day

2) Using the NPP, calculate the efficiency of photosynthesis for the sugar beets.

% Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

We know the NPP, but this value is calculated in g/m²/day, while the Insolation energy is in g/cm²/day. We need to calculate the % Efficiency of Photosynthesis in cm. To do that, we must transform the information.

So if 1 m² = 10,000 cm², then:

10,000cm²----------120 grams/m²/day NPP

1 cm²---------------- (1 x 120) / 10,000 = 0.012 grams/cm²/day NPP

We also know that 1 gr beets = 2,000 cal, and that the Insolation energy is 800 calories/cm²/day

So we need to transform Insolation energy from calories/cm²/day to grams/cm²/day, so:

2,000 calories ----------------- 1 gr beet

800 calories/cm²/day---------X = 0.4 gr beet.

% Efficiency of Photosynthesis = (NPP/Insolation Energy) X 100

% Efficiency of Photosynthesis = (0.012 (gr/cm2/day) /0.4 (gr/cm2/day)) X 100

% Efficiency of Photosynthesis = 3 gr/cm2/day  

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ILL GIVE BRAINLY PLS IM BEING TIMED
Sergeu [11.5K]

Answer:

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