Answer:
180
Step-by-step explanation:
i just did it got it right
Answer:
>
Step-by-step explanation:
brainliest please?
Extraneous solutions are the values that we get when solving equations which aren't really solutions to the equation.
<h3>
What are extraneous solutions?</h3>
Your information is incomplete. Therefore, an overview will be given. An extraneous solution is the root of a transformed equation which is not a root of the original equation since it was excluded from the domain of the original equation.
The reason extraneous solutions exist is simply that some operations produce extra answers, and these operations are a part of the path to solving the problem.
Learn more about equations on:
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Answer:
78
Step-by-step explanation:
The given functions are:

and



When we plug in x=-5, we get:



rewrite the equation set = to 0.
x^2 + 5x - 8 = 0
The quadratic will not factor so you have to use the quadratic formula.
x = (-b + - sqrt(b^2 - 4ac))/2a
x = (5 + - sqrt(25 - 4* 1* -8))/2
x = (5 + - sqrt 57)/2
The x2is not the same as 2x. It is x^2. X tot he second power which makes the problem a quadratic equation. You cannot combine the terms x^2 and -5x because they so not have the same power.