Ask question

Ask question

All categories

3 years ago

14

a chocolate bar measures 50 mm wide 90 mm long and 3 1/2 mm high wills wrapping company is making a wrapper to cover the chocola

te bar use the correct nwt and determine how much paper will be needed to make the wrapper

1 answer:

Amiraneli [1.4K]3 years ago

5 0

I think it is 2250. I am using the b*h/2 to find it.

You might be interested in

Find the unit price if 7 pounds of sugar sells for $2.50

ohaa [14]

2.50 divide by 7= .36 cents for each pound

7 0

3 years ago

Read 2 more answers

A 2.5m long ladder leans against the wall of a building. The base of the ladder is 1.5m away from the wall. What is the height o

katen-ka-za [31]

I’m pretty sure you just use pythag for that so 1.5^2 + h^2 = 2.5^2 and once you solve that you should have your answer and don’t forget to root it after

7 0

2 years ago

Read 2 more answers

Identify the equation in slope intercept from that has a slope of 2 and goes through the point (4, 6).

Mars2501 [29]

Answer:

y = 2x−2

Step-by-step explanation:

You are given a slope and a point, so you can write the equation using point-slope form:

y -k = m(x -h) . . . . . . a line with slope m through point (h, k)

Putting in the numbers given, you have ...

y -6 = 2(x -4)

y = 2x -8 +6 . . . . eliminate parentheses, add 6

y = 2x -2 . . . . . . . collect terms.

__

You know that the slope is the coefficient of x, so the first choice is eliminated right away. Trying the point values in the other equations shows you that they only work for the last choice, as shown above.

2·4 +14 = 22 ≠ 6 . . . . second choice doesn't work
2·4 +6 = 14 ≠ 6 . . . . . third choice doesn't work
2·4 -2 = 6 . . . . . . y = 2x-2 is the equation that works

5 0

3 years ago

Read 2 more answers

Evaluate the expression described below if the number is 4.

Archy [21]

<em>x</em>² - x

<em>x</em> = 4

4² - 4

16 - 4 = 12

Hope this helps!

5 0

3 years ago

Element X is a radioactive isotope such that its mass decreases by 26% every day. If an experiment starts out with 810 grams of

ioda

Answer:

The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

The function to represent the mass of the sample after t days is $A(t) = 810(0.74)^t$

Step-by-step explanation:

Exponential equation of decay:

The exponential equation for the amount of a substance is given by:

$A(t) = A(0)(1-r)^t$

In which A(0) is the initial amount and r is the decay rate, as a decimal.

Hourly rate of change:

Decreases 26% by day. A day has 24 hours. This means that $A(24) = (1-0.26)A(0) = 0.74A(0)$ ; We use this to find r.

$A(t) = A(0)(1-r)^t$

$0.74A(0) = A(0)(1-r)^{24}$

$(1-r)^{24} = 0.74$

$\sqrt[24]{(1-r)^{24}} = \sqrt[24]{0.74}$

$1 - r = (0.74)^{\frac{1}{24}}$

$1 - r = 0.9875$

$r = 1 - 0.9875 = 0.0125$

The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

Starts out with 810 grams of Element X

This means that $A(0) = 810$

Element X is a radioactive isotope such that its mass decreases by 26% every day.

This means that we use, for this equation, r = 0.26.

The equation is:

$A(t) = A(0)(1-r)^t$

$A(t) = 810(1 - 0.26)^t$

$A(t) = 810(0.74)^t$

The function to represent the mass of the sample after t days is $A(t) = 810(0.74)^t$

5 0

3 years ago