Find the number of real number solutions for the equation. x2 – 4x + 4 = 0
1 answer:
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<h2>Range of x </h2><h3>
and x>6</h3><h3>Step-by-step explanation:</h3>
Given AB = 4x + 5, BC = 3x - 2 and AC 9x -5
The sum of the length of any two sides of a triangle is greater than the length of third side.
Case I
AB + BC > AC
⇔4x +5 +3x -2 > 9x -5
⇔7x + 3 >9x - 5
⇔ 7x -9x > -5 -3
⇔-2x > -8
⇔x <4
Case II
if AB+AC > BC
4x +5 +9x -5> 3x -2
⇔13x >3x -2
⇔ 13x -3x> -2
⇔10x > -2
⇔x >
Case III
AC+BC > AB
⇔9x - 5 +3x - 2 > 4x +5
⇔6x -7 > 4x +5
⇔6x -4x >5+7
⇔2x > 12
⇔x > 6
Answer:
21 ft by 28 ft
Step-by-step explanation:
To maximize the area, see the attached.
Perimeter will be 4l+3w which is equal to the fencing perimeter, given as 168
4l+3w=168
Making l the subject then
4l=168-3w
l=42-¾w
Area of individual land will be lw and substituting l with l=42-¾w
Then
A=lw=(42-¾w)w=42w-¾w²
A=42w-¾w²
Getting the first derivative of the above with respect to w rhen
42-w6/4=0
w6/4=42
w=42*4/6=28
Since
l=42-¾w=42-¾(28)=21
Therefore, maximum dimensions are 21 for l and 28 for w
