All categories

2 years ago

How much would I have to deposit now in order to have 150,000 in 18 years

Mathematics

1 answer:

Novosadov [1.4K]2 years ago

3 0

Answer:

I think the answer is $41.66

Step-by-step explanation:

I found how many months it was, which was 216.

Divided 150,000 by 216, which was 694.44.

And lastly, I multiplied 694.44 by 0.06(the same as 6%) and that gave me 41.66.

You might be interested in

Use tables to show which of these ratios are equivalent: 4/6, 10/25, and 6/15

hoa [83]

Answer:

4/6 and 6/15

Step-by-step explanation:

simplify all fractions to lowest possible.

4/6 = 2/3

10/25 = 2/5

6/15 = 2/3

4/6 and 6/15 are equivalent

8 0

3 years ago

What is the solution set of -11 > 1 + a?<br>a > -10<br>a -12

Luda [366]

Answer is 10 because I just took the test

5 0

3 years ago

Read 2 more answers

help At 1:00 P.M. the water level of a pool is 13 inches At 1:30 P.M. the water level is 18 inches At 2:30 the water level is 28

mamaluj [8]

The answer is 5 . because if you count the # it will go to 28

7 0

2 years ago

The number of cups of flour varies directly as the number of rolls made. Four cups of flour are needed to make 24 rolls. How muc

kiruha [24]

14 cups of flour is needed to make 36 rolls. I think it is

6 0

2 years ago

Read 2 more answers

A growth medium is inoculated with 1,000 bacteria, which grow at a rate of 15% each day. What is the population of the culture 6

ddd [48]

Answer:

The population of bacteria after 6 days is 2,313.06

Step-by-step explanation:

Given as :

The initial population of bacteria = i = 1,000 bacteria

The growth rate of bacteria per day = 15%

Let The population of bacteria after 6 days = f

The time period of growth = 6 days

<u>Now, According to question</u>

The population of bacteria after 6 days = initial population × $(1+\dfrac{\textrm rate}{100})^{\textrm time}$

Or, f = i × $(1+\dfrac{\textrm r}{100})^{\textrm t}$

Or, f = 1000 × $(1+\dfrac{\textrm 15}{100})^{\textrm 6}$

Or, f = 1000 × $(1.15)^{6}$

Or, f = 1000 × 2.31306

∴ f = 2,313.06

So,The population of bacteria after 6 days = f = 2,313.06

Hence,The population of bacteria after 6 days is 2,313.06 Answer

3 0

3 years ago