Identify the x-intercept and y-intercept of the line 4x-2y=-12

1 answer:

7 0

To find x-intercept, put the Y value = 0;

4x - 2y = -12

-> 4x -2.0 = -12
-> 4x = -12
-> x = -12/4
-> x = -3

X-intercept: (-3,0)

Now do the reverse to find the y-intercept, X = 0;

4x - 2y = -12

-> 4.0 - 2y = -12
-> -2y = -12 x(-1)
-> 2y = 12
-> y = 12/2
-> y = 6

Y-intercept: (0, 6)

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Solve x2 - 8x - 9 = 0. Rewrite the equation so that it is of the form x2 + bx = c.

barxatty [35]

Answer:

x=9,-1 and $x^2+(-8)x=9$

Explanation:

we have been given with the quadratic equation $x^2-8x-9$

we compare the given quadratic equation with general quadratic equation

general quadratic is $ax^2+bx+c=0$

from given quadratic equation a=1,b= -8,c= -9

substituting these values in the formula for discriminant $D=b^{2}-4ac$

$D=(-8)^2-4(1)(-9)=100$

Now, to find the value of x

Formula is $x=\frac{-b\pm\sqrt{D}}{2a}$

Now, substituting the values we will get

$x=\frac{-(-8)\pm\sqrt{100}} {2}= \frac{8\pm10}{2}=9,-1$

And rewritting the given equation by shifting 9 to right hand side of the given equation and taking minus inside the bracket so as to convert it in the form of

$x^2+bx=c$