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lara31 [8.8K]
3 years ago
5

Use I = PRT to solve.

Mathematics
1 answer:
Mice21 [21]3 years ago
4 0

Answer:

Time T = 15 year

Step-by-step explanation:

Given:

Interest I = $270,000

Principal P = $150,000

Rate R = 12% = 0.12

Find:

Time T

Computation:

I = PRT

270,000 = (150,000)(0.12)(T)

270,000 = (18,000)(T)

Time T = 15 year

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Malachai is doing a 20 miles bike ride. He has cycled 11 miles so far. What percentage of the the total distance has he cycled
Anestetic [448]
11 miles / 20 miles =.55
.55 x 100 = 55%
11/20 is the proportion and you multiply by 100 to gey a percent
another way to solve is
11/20 x 5/5 = 55/100 = 55%
you multiply by 5/5 because it is equal to one and it makes the denominator equal to 100 it also follows the rule that whatever you do to the top you must do with the bottom
5 0
3 years ago
Which of the following correctly names one of the vertices of the triangle<br> below?
anygoal [31]
M. A vertex is a point at which two line segments meet. M is the only point listed and is a point of intersection.
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4 years ago
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I need to know the answer and work
Basile [38]

Answer:

2\sqrt{17}

Step-by-step explanation:

Given:

\sqrt{68}

To find:

Simplified result of the radical

Solution:

If a value is in square root and it is not a perfect square then we can solve it by finding the answer by factoring down it to smaller factors which are perfect squares and finding the square root of the smaller values

Now

68 can be written as

68 = 2 * 2 * 17

The given is

\sqrt{68}

It can be written as

\sqrt{68}=\sqrt{2*2*17}

=\sqrt{2^{2}*17}

Now

\sqrt{a.b}= \sqrt{a}.\sqrt{b}

so given become

\sqrt{68}=\sqrt{2^{2}}*\sqrt{17}

\sqrt{68}=2*\sqrt{17}                          ∵√2² = 2


\sqrt{68}=2\sqrt{17}                  ∵a*√b=a√b                            

4 0
4 years ago
Please Help Quickly!!!<br><br> Find the limit if f(x) = x^3
jeka94

Answer:

Option b. 12

Step-by-step explanation:

This exercise asks us to find the derivative of a function using the definition of a derivative.

Our function is f(x) = x^{3}. Therefore:

f(2+h) = (2+h)^{3}

f(2) = (2)^{3} = 8

Then:

\lim_{h \to \0} \frac{f(2+h)-f(2)}{h}=\lim_{h \to \0} \frac{(2+h)^{3}-8}{h}

Expanding:

\lim_{h \to \0} \frac{(2+h)^{3}-8}{h} =\lim_{h \to \0} \frac{8+ h^{3} +6h(2+h) -8}{h} =\lim_{h \to \0} \frac{h^{3} +6h(2+h)}{h}

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Now, if x=0:

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4 0
3 years ago
What is 8.25 as a fraction in simplest form?
vekshin1
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Simplify by dividing 5 to the numerator and denominator.

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To convert this to a decimal, just divide 5 / 8

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3 0
3 years ago
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