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BartSMP [9]
3 years ago
10

A square fits exactly inside a circle with each of its vertices

Mathematics
1 answer:
tiny-mole [99]3 years ago
3 0

Answer:

5.97

Step-by-step explanation:

If the radius of the circle = r then

pi r^2 = 56

r^2 = 56/pi

r = sqrt(56/pi)

The radius of the circle is equal to half of a diagonal of the square. That is,

r = (1/2) sqrt (2x^2)

= x (sqrt 2)/2

= x/(sqrt 2)

So x = r sqrt 2

= sqrt (56/pi) sqrt 2

= 4 sqrt (7/pi)

= 5.9708

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<em>Comment on the GCF</em>

It can be useful to know Euclid's algorithm for finding the GCF:

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