The answer is B. [x] 2x^2 (21 _ 2pi)
proof
2x^2 (21 _ 2pi)= 42x^2 - 4pix^2= <span>rectangular area- circular area</span>
D, negatives of A and B cancel each other out.
As an equation, we have:
69+42=5+(146-x)
You just have to simplify:
111=5+(146-x)
106=146-x
-40=-x
40=x
Your unknown number is 40
Both a rhombus and a rectangle have diagonals that are perpendicular bisectors, but the ones formed in a square are all congruent, so that is probably the most descriptive one.
The two numbers are 14 and 11
