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vazorg [7]
3 years ago
8

Solve x2 + 10x = 24 by completing the square. Which is the solution set of the equation?

Mathematics
1 answer:
Lilit [14]3 years ago
4 0

Answer:

{ - 12, 2 }

Step-by-step explanation:

Given

x² + 10x = 24

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(5)x + 25 = 24 + 25

(x + 5)² = 49 ( take the square root of both sides )

x + 5 = ± \sqrt{49} = ± 7 ( subtract 5 from both sides )

x = - 5 ± 7

Thus

x = - 5 - 7 = - 12

x = - 5 + 7 = 2

Solution set is { - 12, 2 }

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Find the function r that satisfies the given condition. r'(t) = (e^t, sin t, sec^2 t): r(0) = (2, 2, 2) r(t) = ()
lesantik [10]

Answer:

r(t) = (e^t +1, -cos(t) + 3, tan(t) + 2)

Step-by-step explanation:

A primitive of e^t is e^t+c, since r(0) has 2 in its first cooridnate, then

e^0+c = 2

1+c = 2

c = 1

Thus, the first coordinate of r(t) is e^t + 1.

A primitive of sin(t) is -cos(t) + c (remember that the derivate of cos(t) is -sin(t)). SInce r(0) in its second coordinate is 2, then

-cos(0)+c = 2

-1+c = 2

c = 3

Therefore, in the second coordinate r(t) is equal to -cos(t)+3.

Now, lets see the last coordinate.

A primitive of sec²(t) is tan(t)+c (you can check this by derivating tan(t) = sin(t)/cos(t) using the divition rule and the property that cos²(t)+sin²(t) = 1 for all t). Since in its third coordinate r(0) is also 2, then we have that

2 = tan(0)+c = sin(0)/cos(0) + c = 0/1 + c = 0

Thus, c = 2

As a consecuence, the third coordinate of r(t) is tan(t) + 2.

As a result, r(t) = (e^t +1, -cos(t) + 3, tan(t) + 2).

6 0
3 years ago
A helicopter flew north 325 meters and then flew east 500 meters. How far is the helicopter from its starting point?
kati45 [8]

Answer:

596.34m approx

Step-by-step explanation:

Given data

Let the Starting point be x

A helicopter flew north 325 meters from x

Then flew east 500 meters

Let us apply the Pythagoras theorem to solve for the resultant which is the distance from the starting position

x^2= 325^2+500^2

x^2=105625+250000

x^2= 355625

x= √355625

x=596.34m

Hence the distance from the starting point is 596.34m approx

8 0
3 years ago
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