What is 1 ten more than 9 ones

(08.05 MC) The box plot below shows the number of years that 12 schools have participated in an interschool swimming meet: A box

bearhunter [10]

Answer:

20% of the total schools participated for 6 years or more. This is because the part of the box plot wherein it hits 6 years and above is 20%. Thus, if there are 20 schools, then 20% of it would be 4. In conclusion, there are 4 schools that participated for 6 years or more.

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

1.1

Mkey [24]

<h3>Answer: A) Parallel </h3>

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Explanation:

I've highlighted lines m and k in red (see diagram below). We'll ignore the other lines. On those red lines, I've added blue points with their coordinate locations.

Line m has point A = (-3, 5) and B = (-1, -3). Let's use the slope formula to find the slope through these points

m = (y2-y1)/(x2-x1)

m = (-3-5)/(-1-(-3))

m = (-3-5)/(-1+3)

m = -8/2

m = -4

The slope of line AB, aka line m, is -4.

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Line k has points C = (1, 5) and D = (3, -3) on it. We'll use the slope formula to get...

m = (y2-y1)/(x2-x1)

m = (-3-5)/(3-1)

m = -8/2

m = -4

The slope of line CD, aka line k, is -4

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Both lines m and k have the same slope of -4. Therefore, the two lines are parallel. Parallel lines always have the same slope, but different y intercepts. So these lines will never intersect one another.

3 0

3 years ago

A student is getting ready to take an important oral examination and is concerned about the possibility of having an "on" day or

Tamiku [17]

Answer:

The students should request an examination with 5 examiners.

Step-by-step explanation:

Let <em>X</em> denote the event that the student has an “on” day, and let <em>Y</em> denote the

denote the event that he passes the examination. Then,

$P(Y)=P(Y|X)P(X)+P(Y|X^{c})P(X^{c})$

The events ( $Y|X$ ) follows a Binomial distribution with probability of success 0.80 and the events ( $Y|X^{c}$ ) follows a Binomial distribution with probability of success 0.40.

It is provided that the student believes that he is twice as likely to have an off day as he is to have an on day. Then,

$P(X)=2\cdot P(X^{c})$

Then,

$P(X)+P(X^{c})=1$

⇒

$2P(X^{c})+P(X^{c})=1\\\\3P(X^{c})=1\\\\P(X^{c})=\frac{1}{3}$

Then,

$P(X)=1-P(X^{c})\\=1-\frac{1}{3}\\=\frac{2}{3}$

Compute the probability that the students passes if request an examination with 3 examiners as follows:

$P(Y)=P(Y|X)P(X)+P(Y|X^{c})P(X^{c})$

$=[\sum\limits^{3}_{x=2}{{3\choose x}(0.80)^{x}(1-0.80)^{3-x}}]\times\frac{2}{3}+[\sum\limits^{3}_{x=2}{{3\choose x}(0.40)^{3}(1-0.40)^{3-x}}]\times\frac{1}{3}$

$=0.715$

The probability that the students passes if request an examination with 3 examiners is 0.715.

Compute the probability that the students passes if request an examination with 5 examiners as follows:

$P(Y)=P(Y|X)P(X)+P(Y|X^{c})P(X^{c})$

$=[\sum\limits^{5}_{x=3}{{5\choose x}(0.80)^{x}(1-0.80)^{5-x}}]\times\frac{2}{3}+[\sum\limits^{5}_{x=3}{{5\choose x}(0.40)^{x}(1-0.40)^{5-x}}]\times\frac{1}{3}$

$=0.734$

The probability that the students passes if request an examination with 5 examiners is 0.734.

As the probability of passing is more in case of 5 examiners, the students should request an examination with 5 examiners.

8 0

3 years ago

Is the sum of two monomials always a monomial? Is their product always a monomial?

Ivan

Sum of two monomials is not necessarily always a monomial.

For example:

Suppose we have two monomials as 2x and 5x.

Adding 2x+5x , we get 7x.

So if two monomials are both like terms then their sum will be a monomial.

Suppose we have two monomials as 3y and 4x

Now these are both monomials but unlike, so we cannot add them together and sum would be 3y + 4x , which is a binomial.

So if we have like terms then the sum is monomial but if we have unlike terms sum is binomial.

Product of monomials:

suppose we have 2x and 5y,

Product : 2x*5y = 10xy ( which is a monomial)

So yes product of two monomials is always a monomial.

4 0

3 years ago

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True or false 9 > d, if d = 3

Talja [164]

Answer:

true

Step-by-step explanation:

The left side 9 is greater than the right side 3, which means that the given statement is always true.

3 0

3 years ago