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3 years ago

What is the lcm of each group of numbers 3,9,15

Mathematics

2 answers:

Nina [5.8K]3 years ago

7 0

Answer: 45

Step-by-step explanation:

By factor method,

3 = 1, 3

9= 3, 3

15= 3, 5

LCM= 3*3*5

=45

mamaluj [8]3 years ago

5 0

Answer:

Step-by-step explanation:

Multiples of 3: 3, 6, 9, 12, 15, 18, 27, 30, 33, 36, 39 , 41, 45, ...

Multiples of 9: 9, 18, 27, 36, 45...

Multiples of 15: 15, 30, 45, 60,...

The lowest multiple they have in common is 45

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MAXImum [283]

Answer:

It would take alot of time for be to fill everything out so the simple solution is, complementary angles add up to 90 degrees and supplementary add up to 180 degrees. Simply for complementary do 90 - m<1 = m<2, and for supplementary 180 - m<3 = m<4.

3 0

3 years ago

Use the graph of f '(x) below to find the x values of the relative maximum on the graph of f(x):

Lana71 [14]

Answer:

You have relative maximum at x=1.

Step-by-step explanation:

-Note that f' is continuous and smooth everywhere. f therefore exists everywhere on the domain provided in the graph.

f' is greater than 0 when the curve is above the x-axis.

f' greater than 0 means that f is increasing there.

f' is less than 0 when the curve is below the x-axis.

f' is less than 0 means that f is decreasing there.

Since we are looking for relative maximum(s), we are looking for when the graph of f switches from increasing to decreasing. That forms something that looks like this '∩' sort of.

This means we are looking for when f' switches from positive to negative. At that switch point is where we have the relative maximum occurring at.

Looking at the graph the switch points are at x=0, x=1, and x=2.

At x=0, we have f' is less than 0 before x=0 and that f' is greater than 0 after x=0. That means f is decreasing to increasing here. There would be a relative minimum at x=0.

At x=1, we have f' is greater than 0 before x=1 and that f' is less than 0 after x=1. That means f is increasing to decreasing here. There would be a relative maximum at x=1.

At x=2, we have f' is less than 0 before x=2 and that f' is greater than 0 after x=2. That means f is decreasing to increasing here. There would be a relative minimum at x=2.

Conclusion:

* Relative minimums at x=0 and x=2

* Relative maximums at x=1

3 0

3 years ago

Help me please please

cupoosta [38]

Answer:

(7, 5)

Step-by-step explanation:

AC is the resultant. Point C is 7 units right and 5 units up from point A. If those are what go in your boxes, the resultant is ...

$\displaystyle\left(\,7\,\above\,5\,\right)$

_____

<em>Comment on the question</em>

Vectors can be represented a number of different ways. Components can be given in rectangular or polar form, and the presentation can be made as a row vector, column vector, sum of orthogonal unit vectors, and other ways. We assume this is supposed to be a column vector of the form ...

$\displaystyle\left(x\above y\right)$

7 0

3 years ago

Given: PRbisects ZQPS, PQ = 12units, and PS= 12units

Ganezh [65]

Answer:

Use SAS to show that triangles PRQ and PRS are congruent.

Step-by-step explanation:

Since PR bisects angle QPS, angles QPR and SPR are congruent. By reflexive property of congruence, PR is congruent to itself. Since PQ is congruent to PS, we can use SAS to show that the two triangles are congruent. By CPCTC, QR is congruent to SR.

3 0

2 years ago

Graph y=6x−7<br> Identify the x-intercept.

valina [46]

9514 1404 393

Answer:

x-intercept: 7/6

Step-by-step explanation:

The x-intercept is found by solving for x when y=0.

0 = 6x -7

7 = 6x . . . . . add 7 to both sides of the equation

7/6 = x . . . . divide both sides by 6

The x-intercept is 7/6 = 1 1/6 ≈ 1.167.

The y-intercept is the constant in the given equation: -7. The slope of 6 tells you the line rises 6 units for 1 unit to the right. So, the point (1, -1) is another point on the graph. The line through those two points, (0, -7) and (1, -1), will intersect the x-axis at x=7/6.

6 0

3 years ago