y=x+14 line 1
y=3x+2 line 2
These are both the equation of lines written in slope intercept form
y=mx+b where m is the slope and the point (0,b) is the y intercept.
The first line has a slope of m=1. The 2nd line has a slope of m=3
Since these lines have different slopes, they are not parallel, thus they will cross at some point. What you have to determine is where the lines cross, which will be a point (x,y) that is on both lines.
We already have y solved in terms of x from either equation so we can use substitution to solve the system.
Since y=x+14 from line 1, put x+14 in place of y in the equation of line 2.
x+14=3x+2
solve for x.
Subtract x from both sides...
14= 3x-x+2
14=2x+2
subtract 2 from both sides
14-2=2x
12=2x
divide both sides by 2
6=x
We now have the x value of the common point. Plug the value 6 in for x in one of the original equations and solve for y.
y=6+14
y=20
These two lines cross at the point (6,20) which is a point the two lines have in common.
Hope I helped (SharkieOwO)
Answer:
28.26m^2 (aka. 28.26 meters squared)
Step-by-step explanation:
The area of a circle is A=pi*r^2 where r is the radius of the circle.
Since r=3, then A=pi*3^2=9pi=28.26
Therefore, the area of the merry-go-round is 28.26 square meters
Answer:
yes 2=138 degrees
Step-by-step explanation:
Not hundo perecent sure, sorry if it's wrong, if you want me to show my work then please ask
Answer:
a. −1973700x
b. 0.12
c. 1344
d. −
36.2
Step-by-step explanation:
1.95 = .21(5) + .06m
1.95 = 1.05 + .06m
Solving (if needed)
Subtract 1.05 from each side
1.95 - 1.05 = .06m
.90 = .06m
Divide .06 on both sides
15 = m
