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2 years ago

In parallelogram abcd, m

Mathematics

2 answers:

just olya [345]2 years ago

6 0

What aboout it? please clarify.

ExtremeBDS [4]2 years ago

5 0

What's the rest of the problem? Can't help if we don't have a picture of some sort or if we don't have the rest of the question

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The ratio of men to women in a movie theater is 3:5. As two more men and one more woman walk in, the ratio of men to women becom

34kurt

Answer:

C. 20

Step-by-step explanation:

Let's say M is the original number of men and W is the original number of women.

M / W = 3 / 5

(M+2) / (W+1) = 2 / 3

Let's cross multiply both equations:

5M = 3W

3(M+2) = 2(W+1)

Let's simplify the second equation:

3M + 6 = 2W + 2

3M + 4 = 2W

From the first equation:

M = 3/5 W

Substitute:

3 (3/5 W) + 4 = 2W

9/5 W + 4 = 2W

4 = 1/5 W

W = 20

There were originally 20 women.

Let's check our answer. That would mean that M = 3/5 W = 12.

After 2 men walk in and 1 woman, W = 21 and M = 14, so 14/21 = 2/3. Looks like the answer is correct!

Answer C.

7 0

3 years ago

A sector has angle 2.5 radians and perimeter of 18cm. find the radius of the sector

babunello [35]

Answer:

4 cm

Step-by-step explanation:

Perimeter = 18cm

θ = 2.5 radian

s = rθ, s = Arc length

Perimeter of Sector, P = arc length, s + 2r

Perimeter = rθ + 2r

r = Radius

18cm = r(2.5) + 2r

18cm = 2.5r + 2r

18cm = 4.5r

r = 18 /4.5

r = 4

8 0

2 years ago

Paul needs 2 and 1/4 yards of fabric to make a tablecloth. How many tablecloths can he make from 18 and a half yards of fabric?

Taya2010 [7]

18.5/2.25 = 8.2222222.. So The Answer Is 8.

4 0

3 years ago

Read 2 more answers

What is the measure of Angle ABC A. 120 degrees B. 125 degrees C. 60 degrees D. 55 degrees

Finger [1]

We have the following:

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8 0

10 months ago

Rationalise the denominator of:<br>1/(√3 + √5 - √2)

Paul [167]

Step-by-step explanation:

$\large\underline{\sf{Solution-}}$

Given expression is

$\rm :\longmapsto\:\dfrac{1}{ \sqrt{3} + \sqrt{5} - \sqrt{2} }$

can be re-arranged as

$\rm :\longmapsto\:\dfrac{1}{ \sqrt{3} - \sqrt{2} + \sqrt{5} }$

$\rm \: = \: \dfrac{1}{( \sqrt{3} - \sqrt{2} ) + \sqrt{5} }$

On rationalizing the denominator, we get

$\rm \: = \: \dfrac{1}{( \sqrt{3} - \sqrt{2} ) + \sqrt{5} } \times \dfrac{( \sqrt{3} - \sqrt{2} ) - \sqrt{5} }{( \sqrt{3} - \sqrt{2} ) - \sqrt{5} }$

We know,

$\rm :\longmapsto\:\boxed{\tt{ (x + y)(x - y) = {x}^{2} - {y}^{2} \: }}$

So, using this, we get

$\rm \: = \: \dfrac{ \sqrt{3} - \sqrt{2} - \sqrt{5} }{ {( \sqrt{3} - \sqrt{2} )}^{2} - {( \sqrt{5}) }^{2} }$

$\rm \: = \: \dfrac{ \sqrt{3} - \sqrt{2} - \sqrt{5} }{3 + 2 - 2 \sqrt{6} - 5}$

$\rm \: = \: \dfrac{ \sqrt{3} - \sqrt{2} - \sqrt{5} }{5 - 2 \sqrt{6} - 5}$

$\rm \: = \: \dfrac{ \sqrt{3} - \sqrt{2} - \sqrt{5} }{ - 2 \sqrt{6}}$

$\rm \: = \: \dfrac{ - ( - \sqrt{3} + \sqrt{2} + \sqrt{5}) }{ - 2 \sqrt{6}}$

$\rm \: = \: \dfrac{- \sqrt{3} + \sqrt{2} + \sqrt{5}}{2 \sqrt{6}}$

On rationalizing the denominator, we get

$\rm \: = \: \dfrac{- \sqrt{3} + \sqrt{2} + \sqrt{5}}{2 \sqrt{6}} \times \dfrac{ \sqrt{6} }{ \sqrt{6} }$

$\rm \: = \: \dfrac{- \sqrt{18} + \sqrt{12} + \sqrt{30}}{2 \times 6}$

$\rm \: = \: \dfrac{- \sqrt{3 \times 3 \times 2} + \sqrt{2 \times 2 \times 3} + \sqrt{30}}{12}$

$\rm \: = \: \dfrac{- 3\sqrt{2} + 2 \sqrt{3} + \sqrt{30}}{12}$

Hence,

$\boxed{\tt{ \rm \dfrac{1}{ \sqrt{3} + \sqrt{5} - \sqrt{2} } =\dfrac{- \sqrt{3 \times 3 \times 2} + \sqrt{2 \times 2 \times 3} + \sqrt{30}}{12}}}$

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<h3><u>More Identities to </u><u>know:</u></h3>

$\purple{\boxed{\tt{ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2}}}}$

$\purple{\boxed{\tt{ {(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2}}}}$

$\purple{\boxed{\tt{ {(x + y)}^{3} = {x}^{3} + 3xy(x + y) + {y}^{3}}}}$

$\purple{\boxed{\tt{ {(x - y)}^{3} = {x}^{3} - 3xy(x - y) - {y}^{3}}}}$

$\pink{\boxed{\tt{ {(x + y)}^{2} + {(x - y)}^{2} = 2( {x}^{2} + {y}^{2})}}}$

$\pink{\boxed{\tt{ {(x + y)}^{2} - {(x - y)}^{2} = 4xy}}}$

6 0

2 years ago