u19=-71.74
Step-by-step explanation:
u5=a+4d=-3.7....(1)
u15=a+14d=-52.3....(2)
-10d=48.6
d=-48.6/-10
d=-4.86
Substitute-4.86 into....(1)
u5=a+4(-4.86)=-3.7
a+(-19.44)=-4.7
a=-3.7-(-19.44)
a=15.74
19term=a+18d=?
=15.74+18(-4.86)
=15.74+(-87.48)
19th term =-71.74
This can be solve by first solving the proportionality constant
Number electic outlets rewired is directly proportional to
time spent
4 = (1 ½)a
Let be the proportionality constant
A = 8/3
O = (8/3)(7.5)
o = 20 outlets will jamal rewired if he works for 7.5 hrs
Answer:
The y-intercept of the equation is 100 and represents the initial studio-use fee.
Step-by-step explanation:
In this equation, our t variable (time) is the equivalent of the x-variable on a graph. This is because it is the variable that we 'change' to see its impact on y. We see how the amount of hours affects the price. So our P variable (price) is the equivalent of y on a graph. The y-intercept is where the line crosses the y-axis on a graph. At this point, x=0.
Since P is our y, and t is our x, to find the y-intercept, we simply need to make t = 0.
P = 50(0) + 100
P = 100
Therefore the y-intercept is 100.
In this context, t represents time, so even though the studio has been used for 0 hours, the price is still 100. This is because the 100 represents the initial studio-use fee, and using it for certain amounts of time adds onto the initial fee of $100. The hourly fee is represented by 50t so it costs $50 more for each hour of use.
Hope this helped!
Note that x² + 2x + 3 = x² + x + 3 + x. So your integrand can be written as
<span>(x² + x + 3 + x)/(x² + x + 3) = 1 + x/(x² + x + 3). </span>
<span>Next, complete the square. </span>
<span>x² + x + 3 = x² + x + 1/4 + 11/4 = (x + 1/2)² + (√(11)/2)² </span>
<span>Also, for the x in the numerator </span>
<span>x = x + 1/2 - 1/2. </span>
<span>So </span>
<span>(x² + 2x + 3)/(x² + x + 3) = 1 + (x + 1/2)/[(x + 1/2)² + (√(11)/2)²] - 1/2/[(x + 1/2)² + (√(11)/2)²]. </span>
<span>Integrate term by term to get </span>
<span>∫ (x² + 2x + 3)/(x² + x + 3) dx = x + (1/2) ln(x² + x + 3) - (1/√(11)) arctan(2(x + 1/2)/√(11)) + C </span>
<span>b) Use the fact that ln(x) = 2 ln√(x). Then put u = √(x), du = 1/[2√(x)] dx. </span>
<span>∫ ln(x)/√(x) dx = 4 ∫ ln u du = 4 u ln(u) - u + C = 4√(x) ln√(x) - √(x) + C </span>
<span>= 2 √(x) ln(x) - √(x) + C. </span>
<span>c) There are different approaches to this. One is to multiply and divide by e^x, then use u = e^x. </span>
<span>∫ 1/(e^(-x) + e^x) dx = ∫ e^x/(1 + e^(2x)) dx = ∫ du/(1 + u²) = arctan(u) + C </span>
<span>= arctan(e^x) + C.</span>
Answer:
7*450*.5%
Step-by-step explanation:
