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OverLord2011 [107]
3 years ago
9

Sergey is solving 5x2 + 20x – 7 = 0. Which steps could he use to solve the quadratic equation by completing the square? Check al

l that apply. 5(x2 + 4x + 4) = –7 + 20 x + 2 = 5(x2 + 4x) = 7 5(x2 + 4x + 4) = 7 + 20 5(x2 + 4x) = –7 x + 2 =
Mathematics
2 answers:
Readme [11.4K]3 years ago
8 0

Answer:

5(x^2+4x)=7

Option 2 and 3 is correct.

Step-by-step explanation:

Case (I).

Given equation is

5x^2+20x-7=0

Firstly, we will add of 7 in both sides

5x^2+20x-7+7=7

Now, same variable of opposite sign is cancelled

5x^2+20x=7

Now, taking 5 common from left side

5(x^2+4x)=7

Case (II).

Given equation

5x^2+20x-7=0

Firstly, we will add of 7 in both sides

5x^2+20x=7

Now, we will add of 20 in both sides

5x^2+20x+20=7+20

Now, taking common of 5 from left side

5(x^2+4x+4)=7+20

So, The next step on solving completing square is 5(x^2+4x)=7 and 5(x^2+4x+4)=7+20

Dahasolnce [82]3 years ago
4 0

Answer:

2,3,4 are the answers on edge

Step-by-step explanation:

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