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Leviafan [203]
3 years ago
15

Solve the proportion 44/p = 11/5

Mathematics
2 answers:
Oduvanchick [21]3 years ago
4 0

Answer:

Ifduohxpucxpulxuflulhfdlxlhhlhdxlhlhhdl

Ljccjlxhllcjchlcjlhclhfjfxhhcxcjjj

Jcfjfjgjjjjfjf

Step-by-step explanation:

Sholpan [36]3 years ago
3 0
44   =   11 
----       ----
 p           5    
 
 Cross multiply 

44*5 = 11p 

 You end up with ; 
220    =  11p  

Divide 220 by 11 to get p by itself 

20 = p  <-- that's your answer 
 
hope i helped :)
  
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If set A has 3 elements, then number of elements in A×A×A are​
mrs_skeptik [129]

Answer:

27

Step-by-step explanation:

If set A has 3 elements then number of elements in A*A*A is 27

7 0
3 years ago
one number is 4 more than another number. if 4 times the smaller number is decreased by twice the larger number. the result is 1
soldier1979 [14.2K]

x and x+4 are the numbers

3x=2(x+4)

3x=2x+8

3x-2x=8

x=8

x+4=12


3 0
3 years ago
Finding the length of each side
Fiesta28 [93]

Answer:

see explanation

Step-by-step explanation:

The perimeter is the sum of the 3 sides of the triangle.

Sum the sides and equate to 54, that is

3x + 4x + 5x = 54, that is

12x = 54 ( divide both sides by 12 )

x = 4.5

Thus

AB = 3x = 3 × 4.5 = 13.5 in

BC = 4x = 4 × 4.5 = 18 in

AC = 5x = 5 × 4.5 = 22.5 in

5 0
3 years ago
Find the 7th term of the geometric sequence whose common ratio is 1/3 and whose first term is 5.
wolverine [178]

Answer:

t_7 =\frac{5}{729}

Step-by-step explanation:

We are given that:

First term (a) = 5

common ratio (r) =\frac{1}{3}

The nth term of a geometric sequence is given as:

t_n =ar^{n-1} \\\therefore t_7 =5\times \bigg(\frac{1}{3}\bigg) ^{7-1} \\\therefore t_7 =5\times \bigg(\frac{1}{3}\bigg) ^{6} \\\therefore t_7 =5\times \bigg(\frac{1}{3}\bigg) ^{6} \\\therefore t_7 =5\times \frac{1}{729}\\\\\huge\red{\boxed{\therefore t_7 =\frac{5}{729} }}

8 0
4 years ago
Work out the size of AED. Work out x
Monica [59]

Answer:

a). m∠AED = 70°

b). x = 10°

Step-by-step explanation:

a). Quadrilateral ABDE is a cyclic quadrilateral.

Therefore, by the theorem of cyclic quadrilateral,

Sum of either pair of opposite angle is 180°

m(∠AED) + m(∠ABD) = 180°

m(∠AED) = 180° - 110°

m(∠AED) = 70°

Since, ∠AED ≅ ∠EAD

Therefore, m∠AED = m∠EAD = 70°

b). By triangle sum theorem in ΔABD,

m∠ABD + m∠BDA + m∠DAB = 180°

110° + 40° + m∠DAB = 180°

m∠DAB = 180° - 150°

m∠DAB = 30°

m∠BAE = m∠EAD + m∠BAD

              = 70° + 30° = 100°

By angle sum theorem in ΔACE,

m∠EAC + m∠AEC + m∠ACE = 180°

100° + 70° + x° = 180°

x = 180° - 170°

x = 10°

4 0
3 years ago
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