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zhenek [66]
3 years ago
9

Johnny stretches a spring 40 cm from its resting position. The spring’s constant of proportionality is 20 N/m. What is the sprin

g potential energy?
J=
Physics
1 answer:
sergiy2304 [10]3 years ago
6 0

The spring potential energy is 1.6 J

Explanation:

The elastic potential energy of a spring is given by the equation:

U = \frac{1}{2}kx^2

where

U is the potential energy

k is the spring constant

x is the compression/stretching of the spring

For the spring in this problem, we have:

x = 40 cm = 0.40 m is the stretching

k = 20 N/m is the spring constant

Substituting into the equation, we can find the spring potential energy:

U=\frac{1}{2}(20)(0.40)^2=1.6 J

#LearnwithBrainly

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A vector is given by R 2i + j+3k. Find (a) magnitudes of the x, y, and z components; (b) the ma nitude of R; and (c) the angles
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Answer:

given,

R = 2i + j+3k

a) magnitude in x = 2

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b) magnitude of R

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R = 3.74 units

c) angle between the R and  the x, y, and z axes.

cos \theta_x=\dfrac{2}{3.74}

θ x = 57.72°

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There are four springs stretched by the same mass.
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4 years ago
. A spring has a length of 0.200 m when a 0.300-kg mass hangs from it, and a length of 0.750 m when a 1.95-kg mass hangs from it
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Answer:

29.4 N/m

0.1  

Explanation:

a) From the restoring Force we know that :  

F_r = —k*x  

the gravitational force :  

F_g=mg  

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F_r is the restoring force .

F_g is the gravitational force

g is the acceleration of gravity

k is the constant force  

xi , x2 are the displacement made by the two masses.

Givens:

<em>m1 = 1.29 kg</em>

<em>m2 = 0.3 kg  </em>

<em>x1   = -0.75 m  </em>

<em>x2 = -0.2 m </em>

<em>g   = 9.8 m/s^2  </em>

Plugging known information to get :

F_r =F_g

-k*x1 + k*x2=m1*g-m2*g

k=29.4 N/m

b) To get the unloaded length 1:  

l=x1-(F_1/k)

Givens:

m1 = 1.95kg , x1 = —0.75m  

Plugging known infromation to get :

l= x1 — (F_1/k)  

= 0.1  

 

3 0
3 years ago
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