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vladimir2022 [97]
3 years ago
14

A softball, of mass m = 0.195 kg, is pitched at a speed v0 = 25.3 m/s. Due to air resistance, by the time it reaches home plate

it has slowed by 11.9%. The distance between the plate and the pitcher is d = 13.7 m. Calculate the average force of air resistance, Fair, that is exerted on the ball during its movement from the pitcher to the plate.
Physics
1 answer:
True [87]3 years ago
6 0

Answer:

F = 1.0196N

Explanation:

To give this problem a solution, it is necessary to use the kinematic equations. The equation that describes velocity as a function of acceleration is given by,

v^2 = v_0^2 -2ax

Since there is a loss of 11.9%, in the final speed, that is to say that of the total speed, only 88.1% is the effective one, so

(25.3*88.1\%)^2=25.3^2-2a(13.7)

Re-arrange to find a,

a=-\frac{(25.3*88.1\%)^2-25.3^2}{2*13.7}

a=5.229m/s^2

Applying Newton's second law we have now that

F=ma

F = (0.195)(5.229)

F = 1.0196N

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A centrifuge has an angular velocity of 3,000 rpm, what is the acceleration (in unit of the earth gravity) at a point with a rad
Anna71 [15]

Answer:

a_{r} = 1006.382g \,\frac{m}{s^{2}}

Explanation:

Let suppose that centrifuge is rotating at constant angular speed, which means that resultant acceleration is equal to radial acceleration at given radius, whose formula is:

a_{r} = \omega^{2}\cdot R

Where:

\omega - Angular speed, measured in radians per second.

R - Radius of rotation, measured in meters.

The angular speed is first determined:

\omega = \frac{\pi}{30}\cdot \dot n

Where \dot n is the angular speed, measured in revolutions per minute.

If \dot n = 3000\,rpm, the angular speed measured in radians per second is:

\omega = \frac{\pi}{30}\cdot (3000\,rpm)

\omega \approx 314.159\,\frac{rad}{s}

Now, if \omega = 314.159\,\frac{rad}{s} and R = 0.1\,m, the resultant acceleration is then:

a_{r} = \left(314.159\,\frac{rad}{s} \right)^{2}\cdot (0.1\,m)

a_{r} = 9869.588\,\frac{m}{s^{2}}

If gravitational acceleration is equal to 9.807 meters per square second, then the radial acceleration is equivalent to 1006.382 times the gravitational acceleration. That is:

a_{r} = 1006.382g \,\frac{m}{s^{2}}

6 0
3 years ago
Which SPF level should a person look for in sunscreen as part of planning a day at the beach? pls i need it now
slega [8]

30

Hope you do well on the test and hope this helps!

3 0
4 years ago
1. True or False: Most things in motion are accelerating, few things in real life move at a constant speed.
lord [1]
1. False
2. Positive
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5 0
3 years ago
starting at a position of 0 m, if the man is moving at a constant velocity of 2 m/s, it will take seconds for him to reach a pos
Harman [31]

The calculated time is 6 seconds.

Time is defined by physicists as the flow of events from the past through the present and into the future. In essence, a system is timeless if it is unchanging. When describing events that take place in three-dimensional space, time can be thought of as the fourth dimension of reality. Even if time isn't directly connected to energy, it is undoubtedly connected to many other components of energy. For instance, the movement of energy across the universe can affect the direction of time (from the past to the future).

V= 2 m/s

d=12 m

t=?

we know that velocity=displacement / time

time= displacement / velocity

= 12/2

=6 seconds

the calculated time is 6 seconds.

Learn more about time here-

brainly.com/question/28050940

#SPJ4

4 0
1 year ago
On planet Earth, which of these measurements would be the same for an object?
Ber [7]

Answer:

a

Explanation:

a is he answers . mass and density

3 0
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