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wel
3 years ago
12

When the two surfaces of a thin film are parallel and the light is incident at some angle what fringes are formed? A. Circular B

. Elliptical C. Parabolic D. Straight and why?
Physics
1 answer:
lord [1]3 years ago
8 0

Answer:

The correct option is;

A. Circular

Explanation:

Some of the light that impinges on the surface are reflected and the rest are transmitted to a different medium

At the surface of the next medium also, some of the light are transmitted while the others are reflected and refracted through the first medium

The speed of light (and hence the wavelength and color) refracted through the thin film is changed as the distance the refracted light travels through the thin film is increased as we move away from the point directly in the front view to some distance as the reflected light path from those distance to the eye is increased due to their inclination giving them a different wavelength which are all equal at a radial distance from the eye hence forming a circular fringes.

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Answer:

88.34 N directed towards the center of the circle

Explanation:

Applying,

F = mv²/r................... Equation 1

F = Force needed to keep the mass in a circle, m = mass of the mass, v = velocity of the mass, r = radius of the circle.

But,

v = 2πr/t................... Equation 2

Where t = time, π = pie

Substitute equation 2 into equation 1

F = m(2πr/t)²/r

F = 4π²r²m/t²r

F = 4π²rm/t²............. Equation 3

From the question,

Given: m = 0.8 kg, r = 0.7 m, t = 0.5 s

Constant: π = 3.14

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F = 4(3.14²)(0.7)(0.8)/0.5²

F = 88.34 N directed towards the center of the circle

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3 years ago
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If air resistance can be neglected, how does the acceleration of a ball that has been tossed straight upward compare with its ac
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3 years ago
The gravitational force, F, between an object and the Earth is inversely proportional to the square of the distance from the obj
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<h2>Weight of astronaut 2450 miles above the Earth is 80.38 pounds</h2>

Explanation:

Given that gravitational force, F, between an object and the Earth is inversely proportional to the square of the distance from the object and the center of the Earth.

             F=\frac{k}{r^2}

Where F is gravitational force  between an object and the Earth, r is the distance from the object and the center of the Earth and k is a constant.

Radius of Earth = 4000 miles

In case 1 an astronaut weighs 209 pounds on the surface of the Earth,

              209=\frac{k}{4000^2}\\\\k=3.344\times 10^9

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Weight of astronaut 2450 miles above the Earth is 80.38 pounds  

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