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Sav [38]
3 years ago
8

a parking garage charges $5 for the first hour of parking and $1.75 for each additional hour. if y represents the total cost and

x represents the total number of hours parked in the garage, which function rule describes this pattern
Mathematics
1 answer:
victus00 [196]3 years ago
6 0
In this exact order:
5+1.75x=y
Sorry for the wait..Hope this helps
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Help me!! A water tank is 1/8 full. The tank is 3/4 full when 42 gallons of water is added to the tank. How much can the water t
chubhunter [2.5K]

Answer(s):

1.) 56 gallons

2.) 7 gallons

3.) 28 gallons

Step-by-step explanation:

<u><em>Q1: How much water can the tank hold?</em></u>

Based on the question, we know that 3/4 of the tank equals 42 gallons. Divide 42 by the numerator, 3.

42/3 = 14

Now, multiply 14 by the denominator, 4.

14 x 4 = 56.

<em><u>So, the tank can hold 56 gallons.</u></em> [If you'd like to double check this answer, take the fraction 42/56 and simplify it to get 3/4.

<u><em>Q2: How much water was originally in the tank?</em></u>

We know that the tank's maximum capacity is 56 gallons. So, if it was 1/8 originally full, multiply 56 by 1/8. [Remember that 56 as a fraction can be written as 56/1]

1/8(56/1) = 7

<u><em>This means that the tank was originally 7 gallons full.</em></u> [If you'd like to double check this answer, take the fraction 1/8 and multiply the numerator and denominator by 7. This gets you 7/56, or 7 gallons out of the total capacity, 56 gallons.]

<u><em>Q3: How much water is in the tank when it is 1/2 full?</em></u>

Earlier, we found out that the maximum capacity of the tank is 56 gallons. To find out how many gallons it holds when its half full, divide 56 by 2.

56/2 = 28

<em><u>So, when the tank is 1/2 full, it contains 28 gallons.</u></em> [If you want to double check this answer, take  the fraction 28/56 and simplify it. When you do, you get 1/2.]

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Let \vec a = \langle -2, 3 \rangle, we need to determine \vec v = 2\cdot \vec a, which can be found by applying the following property:

\alpha \cdot \langle x,y \rangle = \langle \alpha \cdot x, \alpha \cdot y\rangle, \forall \,\alpha,x,y\in \mathbb{R} (1)

Then,

\vec v = 2\cdot \langle -2,3 \rangle

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