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3 years ago

15

What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (−4,

−3)?

2 answers:

arsen [322]3 years ago

9 0

Answer:

C, y + 3 = 1/4 (x + 4).

I just took the test and got it wrong because of the other person who answered haha.

blondinia [14]3 years ago

5 0

Y-(-3)=m(x-(-4)..........Simplified would be y+3=m(x+4)

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Angles. If m and m measures of both angles.<br> K =

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3 years ago

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Can someone find the answer key for this

snow_tiger [21]

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4 years ago

Please help me find out what the question marks are

quester [9]

Question a

g(x) times $\sqrt{x-5}=\sqrt{x^2-5}$
divide both sides by √(x-5)
$g(x)=\frac{\sqrt{x^2-5}}{\sqrt{x-5}}$
$g(x)=\frac{(\sqrt{x-5})(\sqrt{x^2-5})}{x-5}$
$g(x)=\frac{\sqrt{x^3-5x^2-5x+25}}{x-5}$

question b
$g(x) \space\ times \space\ 1+\frac{1}{x}=x$
divide both sides by 1+1/x
$g(x)=\frac{x}{1+\frac{1}{x}}$
times by x/x
$g(x)=\frac{x^2}{x+1}$

question c
$\frac{1}{x} \space\ times \space\ f(x)=x$
times both sides by x
$f(x)=x^2$

question d
the (f*g)(x) collumn seems to have a domain of only x is greater than or equal to 0?
so maybe we squared the whole thing, ya
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ah, ya
basically
$|x|=(\sqrt{x})^2=(\sqrt{x})(\sqrt{x})$
so f(x)=√x

a. $g(x)=\frac{\sqrt{x^3-5x^2-5x+25}}{x-5}$
b. $g(x)=\frac{x^2}{x+1}$
c. $f(x)=x^2$
d. $f(x)=\sqrt{x}$

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4 years ago

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k0ka [10]

Answer:

if you wanna find x

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3 years ago

Members of a softball team raised $1334.50 to go to a tournament. They rented a bus for $779.50 and budgeted $46.25 per player f

grin007 [14]

Answer:

12

Step-by-step explanation:

The most important factor is the total budget $1334.50, for the softball tournament.

1. Subtract $779.50 from $1334.50 = $555

2. We have $555 left, and a budget of $46.25 per player for meals

3. Divide 555/46.25 = 12

4. 12 softball players can be brought to the tournament

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2 years ago

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