The population of a city is 1,503,049. The land area of the city is 181.5 km².

2 answers:

7 0

Population density is population divided by area. So

City: 1,503,049 people / 181.5 km^2 = 8281.262 = 8281 people/km^2

Watering hole. Same thing, population divide by area. Only gotcha is the area needs to be calculated. Using A = pi r^2, you get
3.14 * (34 km)^2 = 3629.84 km^2

32/3629.84 = 0.008816 = 0 antelopes/km

Chunk of mahogany wood.
Take the volume and multiply by the density. So
1728 cm^3 * 0.71 g/cm^3 = 1226.88 g

Gold bar.
Same thing. Volume multiplied by density. So
51.8 cm^3 * 19.3 g/cm^3 = 999.74 g

And finally, the sugar maple. This one is slightly trickier. You first need to calculate the volume of the block of wood. So divide the mass by the density.

82.8 g / 0.69 g/cm^3 = 120 cm^3

Now you know the length and width are 5x4 = 20 cm^2. So calculate the height by dividing the volume by 20 cm^2. So
120 cm^3 / 20 cm^2 = 6 cm.

Tresset [83]4 years ago

5 0

1.) 8,281 people/km²
2.)
3.) 1226.88 grams
4.) 999.74 grams
5.) 6

I am not sure about number 2.

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55.5% repeating as a decimal

liberstina [14]

Answer:

0.555

Step-by-step explanation:

When you ask, "What is 55.5 as a decimal?", we assume you want to know what 55.5 percent is as a decimal. In other words, 55.5 percent converted to decimal.

First, we will tell you why it is useful to know 55.5 as a decimal.

Normally, to calculate 55.5 percent, you would multiply a number by 55.5 percent and then you would take the product of that and divide it by 100 to get the answer.

Instead, you can simply multiply a number by 55.5 as a decimal to get the answer.

55.5 percent means 55.5 per hundred. Therefore, to get 55.5 as a decimal, all you have to do is divide 55.5 by 100 like so:

55.5 ÷ 100 = 0.555

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4 years ago

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Farmer Jones, and his wife, Dr. Jones, decide to build a fence in their field, to keep the sheep safe. Since Dr. Jones is a math

alex41 [277]

Answer: $\frac{8}{3}\times \sqrt{\frac{2}{5}}$

Step-by-step explanation:

Given two upward facing parabolas with equations

$y=6x^2 & y=x^2+2$

The two intersect at

$6x^2=x^2+2$

$5x^2=2$

$x^2$ = $\frac{2}{5}$

x= $\pm \sqrt{\frac{2}{5}}$

area enclosed by them is given by

A= $\int_{-\sqrt{\frac{2}{5}}}^{\sqrt{\frac{2}{5}}}\left [ \left ( x^2+2\right )-\left ( 6x^2\right ) \right ]dx$

A= $\int_{\sqrt{-\frac{2}{5}}}^{\sqrt{\frac{2}{5}}}\left ( 2-5x^2\right )dx$

A= $4\left [ \sqrt{\frac{2}{5}} \right ]-\frac{5}{3}\left [ \left ( \frac{2}{5}\right )^\frac{3}{2}-\left ( -\frac{2}{5}\right )^\frac{3}{2} \right ]$