What are polymers?

The first step in the process used to recover zinc metal from zinc sulfide ore is the reaction of zinc sulfide with oxygen gas t

Vikentia [17]

Answer : The mass of oxygen consumed in the reaction is 14.6 grams.

Explanation :

First we have to calculate the change in moles of oxygen.

Formula used :

$w=\Delta nRT$

or,

$\Delta n=\frac{w}{RT}$

where,

w = work done = 850.1 J

$\Delta n$ = change in moles of gas = ?

R = gas constant = 8.314 J/mol.K

T = temperature = 675 K

Now put all the given values in the above formula, we get:

$\Delta n=\frac{850.1J}{(8.314J/mol.K)\times (675K)}=0.152mol$

Now we have to calculate the mass of oxygen consumed.

The balanced chemical reaction is,

$2ZnS(s)+3O_2(g)\rightarrow 2ZnO(s)+2SO_2(g)$

Here, the volume changes of solids can be ignored.

From the balanced chemical reaction, we conclude that

The number of moles oxygen required for the complete reaction = 3

Change in mole of oxygen = 0.152 mol

Molar mass of $O_2$ = 32 g/mol

So,

The mass of oxygen consumed = 3 x 0.152 mol x 32 g/mol = 14.6 g

Therefore, the mass of oxygen consumed in the reaction is 14.6 grams.

4 0

3 years ago

Tris has a molecular weight of 121 g/mol. How many grams of Tris would you need to make 100 mL of a 100 mM solution of Tris

Zepler [3.9K]

Answer:

1.21 g of Tris

Explanation:

Our solution if made of a solute named Tris

Molecular weight of Tris is 121 g/mol

[Tris] = 100 mM

This is the concentration of solution:

(100 mmoles of Tris in 1 mL of solution) . 1000

Notice that mM = M . 1000 We convert from mM to M

100 mM . 1 M / 1000 mM = 0.1 M

M = molarity (moles of solute in 1 L of solution, or mmoles of solute in 1 mL of solution). Let's determine the mmoles of Tris

0.1 M = mmoles of Tris / 100 mL

mmoles of Tris = 100 mL . 0.1 M → 10 mmoles

We convert mmoles to moles → 10 mmol . 1mol / 1000mmoles = 0.010 mol

And now we determine the mass of solute, by molecular weight

0.010 mol . 121 g /mol = 1.21 g

8 0

3 years ago

What would it be like if Earth did not rotate?

kolezko [41]

There would be no day and night :(

7 0

3 years ago

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PLEASE HELP!!!!!!!!!!! WILL AWARD 50 POINTS!!!!!!!!!111

Vinil7 [7]

I am pretty sure the answer is . But I might be wrong.

3 0

3 years ago

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A sample of gas has a volume of 20.0 liters at 22.0° C. If the pressure remains constant, what is the volume at 100.0° C?

miv72 [106K]

The problem applies Charles' law since constant pressure with varying volume and temperature are given. Assuming ideal gas law, the equation to be used is $\frac{ V_{1} }{ T_{1} }$ = $\frac{ V_{2} }{ T_{2} }$ . We make sure the temperatures are expressed in Kelvin, hence the given added with 273. The volume 2 is equal to 25.2881 liters.

6 0

3 years ago

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