The equation of the line which has a gradient of 2 and passes through the point (1,4) is y = 2x + 2.
We have given that,
A line that has a gradient of 2 and passes through the line (1, 4).
We have to determine the equation of the line,
<h3>What is the gradient?</h3>
The gradient also known as the slope is the defined as
Gradient (m) = change in y coordinate / change in x coordinate
The equation of a line passing through a given point is given by the following equation
y – y₁ = m(x – x₁)
How to determine the equation of the line passing through point (1,4)
x coordinate (x₁) = 1
y coordinate (y₁) = 4
Gradient (m) = 2
Equation =
y – y₁ = m(x – x₁)
y – 4 = 2(x – 1)
Clear bracket
y – 4 = 2x – 2
Make y the subject by adding 4 to both sides
y – 4 + 4 = 2x – 2 + 4
y = 2x + 2
The equation of the line which has a gradient of 2 and passes through the point (1,4) is y = 2x + 2.
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9514 1404 393
Answer:
x = (ab +a +b +c)/(a +b)
Step-by-step explanation:
Eliminate parentheses, subtract left terms not containing x, divide by the coefficient of x.
Answer:
18
Step-by-step explanation:
Answer:
x = 20
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180°
Using ΔAHC , then
∠ACH = 180 - (2x + 100) = 180 - 2x - 100 = 80 - 2x
∠ECD = ∠ACB ( vertical angles are congruent ), thus
∠ECD = ∠ACH + ∠HCB, that is
3x = 80 - 2x + x
3x = 80 - x ( add x to both sides )
4x = 80 ( divide both sides by 4 )
x = 20
I believe its 50 because 0.35x50=17.5 (35%=0.35)
