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FrozenT [24]
3 years ago
14

There is an average of 3.5×10−2 kilograms of dissolved salt in each liter of seawater.

Mathematics
2 answers:
allsm [11]3 years ago
6 0
<span>2.3x10^19 kg This is a matter of multiplication using scientific notation. First, multiply the mantissas 3.5 * 6.6 = 23.1 Then add the exponents -2 + 20 = 18 So we initially have 23.1x10^18 But 23 is too large (the number has to be greater than or equal to 1 and less than 10). So divide the 23.1 by 10 and add 1 to the exponent, getting 2.31x10^19 Then since the least accurate value we have for input has only 2 significant digits, round the result to 2 significant digits, getting 2.3x10^19 kg</span>
olasank [31]3 years ago
6 0

IT IS 2.31, I AM TELLING YOU THIS IS 2.31

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3 0
3 years ago
. Imagine a game of 3 players where exactly one player wins in the end and all players have equal chances of being the winner. T
lbvjy [14]

Answer:

5/9

Step-by-step explanation:

Number of players = 3

number of times game is repeated = 4

P( any person wins a game ) = 1/3

P ( any person does not win a game ) = 1 - 1/3 = 2/3

P ( any person wins no game in 4 attempts ) = ( 2/3 )^4 = 16/81

<em>Note : each player has equal chance of winning </em>

<u>Find the probability that there is at least one person who wins no games </u>

lets represent the probability of each player not wining a game with alphabet A

A1 = player 1 wins no game

A2 = player 2 wins no game

A3 = players 3 wins no game

Applying the inclusion-exclusion formula

<em>P( A1 ∪ A2 U A3 )</em><em> = P(A1 ) + P(A2) + P(A3) - P( A1 ∩ A2 ) - P( A2 ∩ A3 ) - P( A1            ∩ A3 )  + P( A1 ∩ A2 ∩ A3 ) </em>

where

P( A1 ∩ A2 ) = P( A1 wins all games )

P ( A1 wins all games in 4 attempts ) = ( 1/3 )^4 = 1/81

P( A1 ∩ A2 ∩ A3 ) = P ( no players wins any game in 4 attempts ) = 0

Hence

P( A1 ∪ A2 U A3 ) = 16/81 + 16/81 + 16/81 - 1/81 - 1/81 - 1/81 - 0 = 5/9

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