So you should label the x axis and y axis like I did then you use the formula!
Answer:
![\sf \dfrac{\pi}{3}\:\:and\:\:\sqrt[\sf 3]{\sf 25}](https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B%5Cpi%7D%7B3%7D%5C%3A%5C%3Aand%5C%3A%5C%3A%5Csqrt%5B%5Csf%203%5D%7B%5Csf%2025%7D)
Step-by-step explanation:
<u>Definitions</u>
Integer: A whole number that can be positive, negative, or zero.
Rational Number: A number that can be expressed as the ratio of two integers (where the denominator does not equal zero).
Irrational Number: A real number that <u>cannot</u> be written as a rational number.


Therefore, -8.2183 can be expressed as a <u>rational number</u>.
π is an <u>infinite decimal</u>, so it cannot be expressed as a rational number.

is an irrational number.

As 11 can be expressed as ¹¹/₁ then 9 + √4 is <u>rational</u>.
<u>Conclusion</u>
Therefore, the numbers that are irrational are:
![\sf \dfrac{\pi}{3}\:\:and\:\:\sqrt[\sf 3]{\sf 25}](https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B%5Cpi%7D%7B3%7D%5C%3A%5C%3Aand%5C%3A%5C%3A%5Csqrt%5B%5Csf%203%5D%7B%5Csf%2025%7D)
Answer: 
Step-by-step explanation:
In order to solve this exercise it is important to remember the multiplication of signs. Notice that:

In this case you have the following expression given in the exercise:

Where the variable is "j".
When you multiply signs, you get:

Now you need to identify that like terms and then you need to add them (or combine them). So, applying this procedure you get that the simplified form of the expression is the shown below:

As you can observe, you get a 2nd degree binomial.
Answer:
b) 690 - 7.5*t
c) 0 < t < 92s time (t) is independent quantity
d) 0 < s < 690ft distance from bus stop (s) is dependent quantity
e) f(0) = 690 ft away from bus stop , f(60.25) = 238.125 ft away from bus stop
Step-by-step explanation:
Part a - see diagram
part b
initial distance from bus stop s0 = 690 ft
distance covered = 7.5*t
s = s0 - distance covered
s = 690 - 7.5*t = f(t)
part c
s = 0 or s = 690
0 = 690 -7.5*t
t = 92 s
Hence domain : 0 < t < 92s time (t) is independent quantity
part d
s = 0 or s = 690
Hence range : 0 < s < 690ft distance from bus stop (s) is dependent quantity because it depends on time (t)
part e
f(0) is s @t = 0
f(0) = 690 ft away from bus stop
f(60.25) is s @t = 60.25
f(60.25) = 690 - 7.5*60.25 = 238.125 ft away from bus stop.