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Elan Coil [88]
3 years ago
7

A student got an 80% on a test that had 40 questions on it. How many questions did the student get correct?

Mathematics
1 answer:
evablogger [386]3 years ago
6 0
The student got 32 questions correct.
40 x 0.8 = 32
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As part of a screening process, computer chips must be operated in an oven at 145 °C. Ten minutes after starting, the temperatur
Novosadov [1.4K]

Answer:

Step-by-step explanation:

I solved this using initial conditions and calculus, so I hope that's what you are doing in math.  It's actually NOT calculus, just a concept that is taught in calculus.

The initial condition formula we need is

y=Ce^{kt}

Filling in our formula with the 2 conditions we are given:

65=Ce^{10k}   and   85=Ce^{15k}

With those 2 equations, we have 2 unknowns, the C (initial value) and the k (the constant). We know that the initial value (or starting temp) for both conditions is the same, so we solve for C in one equation, sub it into the other equation and solve for k.  If

65=Ce^{10k} then

\frac{65}{e^{10k}}=C which, by exponential rules is the same as

C=65e^{-10k}

Since that value of C is the same as the value of C in the other equation, we sub it in:

85=65e^{-10k}(e^{15k})

Divide both sides by 65 and use the rules of exponents again to get

\frac{85}{65}=e^{-10k+15k} which simplifies down to

\frac{85}{65}=e^{5k}

Take the natural log of both sides to get

ln(\frac{85}{65})=5k

Do the log thing on your calculator to get

.2682639866 = 5k and divide both sides by 5 to find k:

k = .0536527973

Now that we have k, we sub THAT value in to one of the original equations to find C:

65=Ce^{10(.0536527973)}

which simplifies down to

65=Ce^{.536527973}

Raise e to that power on your calculator to get

65 = C(1.710059171) and divide to solve for C:

C = 38.01038064

Now sub in k and C to the final problem when t = 23:

y=38.01038064e^{(.0536527973)(23)} which simplifies a bit to

y=38.01038064e^{1.234014338}

Raise e to that power on your calculator to get

y = 38.01038064(3.434991111) and

finally, the temp at 23 minutes is

130.565

6 0
3 years ago
Tom wants to place a photograph that is 8.5 inches wide on his science fair poster. His poster board is 21.25 inches wide. How f
SOVA2 [1]

Answer:

6 3/8 inches (6.375 inches)

Step-by-step explanation:

For simplicity we'll assume that both the photo and the poster board are square.  To determine the width of the border, subtract 8.5 inches from the poster board width 21.25 inches, obtaining 12.75 inches, and then divide that 12.75 inches by 2:  6.375 inches (6 3/8 inches).  

Set the photo 6 3/8 inches from each edge of the poster board.

6 0
3 years ago
To start, you have $63.75. You earn additional money babysitting. Then you purchase a new pair of shoes for $109.99. You now hav
Romashka-Z-Leto [24]

Answer:

Step-by-step explanation:

8 0
3 years ago
3w - 11 = 25<br> can someone answer this plz
adoni [48]

Answer:

w = 12

Step-by-step explanation:

3w = 11 + 25

3w = 36

w = 12

Hope that helps!

3 0
3 years ago
Read 2 more answers
I need graph help plz ​
Likurg_2 [28]

Answer:

Step-by-step explanation:

Part A

x-intercepts of the graph → x = 0, 6

Maximum value of the graph → f(x) = 120

Part B

Increasing in the interval → 0 ≤ x ≤ 3

Decreasing in the interval → 3 < x ≤ 6

As the price of goods increase in the interval [0, 3], profit increases.

But in the price interval of (3, 6] profit of the company decreases.

Part C

Average rate of change of a function 'f' in the interval of x = a and x = b is given by,

Average rate of change = \frac{f(b)-f(a)}{b-a}

Therefore, average rate of change of the function in the interval x = 1 and x = 3 will be,

Average rate of change = \frac{f(3)-f(1)}{3-1}

                                         = \frac{120-60}{3-1}

                                         = 30

6 0
3 years ago
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