The Standard Normal Distribution Curve
Since the data is insufficient. Let us denote that n1 = 100, n2 = 100X1 = 38. X2 = 40
So looking for the p value:
p = (38+ 40) / (100 + 100) = 0.39
z = (38/100 - 40/100)/√ (0.39*(1-0.39)*(1/100 + 1/100))= -0.2899
P-value = P (|z| > 0.2899) = 0.7718
Answer:
C
Step-by-step explanation:
to figure this out, lets understand how decimals work
a decimal number in the tens place before the decimal
↓ here
0.00
that number will be the same number as the numerator or top number of a fraction in tenths
↓ here
0/10
so say it was 4/10 we needed to find, we would look on the number line for 0.40 like in answer choice B (NOT THE CORRECT ANSWER FOR THIS PROBLEM)
hope this helps you out on your work :)
Answer:
Marquice sold 20 tickets and Tim sold 25 tickets
Step-by-step explanation:
Let us assume that Tim sold x number of tickets, Marquice sold 25% more x or 1.25x. ATQ, x+1.25x=45. x=20. So Marquice sold 20 tickets and Tim sold 25 tickets
We can write and solve the differential equation that fits the statement given;
dy/dt = k(50-t)
∫dy = ∫ k(50-t)dt
= ∫ (50k - kt) dt
therefore;
y = 50kt - k/2(t²) + C
Alternatively, can be written as
y = - k/2 (50-t)² + C)
