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Butoxors [25]
3 years ago
11

How is power defined?

Physics
2 answers:
tatiyna3 years ago
7 0

The correct answer to this question is D) The rate at which work is accomplished.

EXPLANATION:

Let us consider a body performs W amount of work due to the application of some external forces.

Let the body does that work during the time interval of t seconds.

Hence, the power of the body is defined as the rate of doing work or the work done per unit time. We know that energy is the capacity to do work. So, power can be defined as the rate of consumption of energy.

Mathematically power can be written as -

                              Power P = \frac{W}{t}.

Hence, the correct definition of power is that the rate at which work is accomplished.

zzz [600]3 years ago
6 0

The power is the rate at which work is accomplished, option D is correct.

Further Explanation:

The power is the rate of transformation energy which is used by another body.

The power is the quantity with only magnitude so it is a scalar quantity. <u>The standard of international unit is watt, it is also written as J/s</u>. The standard of international unit watt in honor of James Watt.

A quantity is said as a vector if it has some magnitude and direction in order to give the details regarding the quantity.

A quantity is said as a scalar if it has only the magnitude in order to give the details regarding the quantity.

Concept:

The term power is defined as “The rate at which the work is finished or the energy is transferred from one place to another or transformed into another form.”

The term energy is defined as the capacity to do work or result in some displacement by applying some force.

The expression for power is:

\fbox{\begin\\p =\dfrac{{\Delta w}}{{\Delta t}}\end{minispace}}

Here, p is the power, \Delta w is the change in energy and \Delta t is the change in the time.

Therefore, the power is the rate at which work is accomplished, option D is correct.

Learn more:

1. Work and power brainly.com/question/9566221

2. Calculate power brainly.com/question/2829572

3. Energy and SI unit https://brainly.in/question/1227001

Answer Details:

Grade: Middle school

Subject: Physics

Chapter: Kinematics

Keywords:

Define, power, quantity, work, accomplished, direction, total distance, object, moved, rate, option, D.

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What is the wavelength of a 6.00*10^2 Hz sound wave in air at 20C
Alex Ar [27]

Answer:

Solution

λ=v/n

Here, v=344 m s−1

n=22 MHz =22×106 Hz

λ=344/22×106=15.64×10−6m=15.64μm.

5 0
2 years ago
Amy uses 20N of force to push a lawn mower 10 meters. How much work does she do? *
babunello [35]

She does 200J .

We know she uses 20N of force and 10m is the distance. We multiply both numbers and we are given our answer of 200J. Hope this was helpful. :)

4 0
3 years ago
A car has a mass of 900 kg and a truck has a mass of 1800 kg. In which of the following situations would they have the same mome
lozanna [386]

A car has a mass of 900 kg and a truck has a mass of 1800 kg. In which of the following situations would they have the same momentum?A car has a mass of 900 kg and a truck has a mass of 1800 kg. In which of the following situations would they have the same momentum?

8 0
3 years ago
1) A thin ring made of uniformly charged insulating material has total charge Q and radius R. The ring is positioned along the x
allochka39001 [22]

Answer:

(A) considering the charge "q" evenly distributed, applying the technique of charge integration for finite charges, you obtain the expression for the potential along any point in the Z-axis:

V(z)=\frac{Q}{4\pi (\epsilon_{0}) \sqrt{R^{2} +z^{2}}  }

With (\epsilon_{0}) been the vacuum permittivity

(B) The expression for the magnitude of the E(z) electric field along the Z-axis is:

E(z)=\frac{QZ}{4\pi (\epsilon_{0}) (R^{2} +z^{2})^{\frac{3}{2} }    }

Explanation:

(A) Considering a uniform linear density λ_{0} on the ring, then:

dQ=\lambda dl (1)⇒Q=\lambda_{0} 2\pi R(2)⇒\lambda_{0}=\frac{Q}{2\pi R}(3)

Applying the technique of charge integration for finite charges:

V(z)= 4\pi (ε_{0})\int\limits^a_b {\frac{1}{ r'  }} \, dQ(4)

Been r' the distance between the charge and the observation point and a, b limits of integration of the charge. In this case a=2π and b=0.

Using cylindrical coordinates, the distance between a point of the Z-axis and a point of a ring with R radius is:

r'=\sqrt{R^{2} +Z^{2}}(5)

Using the expressions (1),(4) and (5) you obtain:

V(z)= 4\pi (\epsilon_{0})\int\limits^a_b {\frac{\lambda_{0}R}{ \sqrt{R^{2} +Z^{2}}  }} \, d\phi

Integrating results:

V(z)=\frac{Q}{4\pi (\epsilon_{0}) \sqrt{R^{2} +z^{2}}  }   (S_a)

(B) For the expression of the magnitude of the field E(z), is important to remember:

|E| =-\nabla V (6)

But in this case you only work in the z variable, soo the expression (6) can be rewritten as:

|E| =-\frac{dV(z)}{dz} (7)

Using expression (7) and (S_a), you get the expression of the magnitude of the field E(z):

E(z)=\frac{QZ}{4\pi (\epsilon_{0}) (R^{2} +z^{2})^{\frac{3}{2} }    } (S_b)

4 0
3 years ago
A cannonball is launched from the ground at an angle of 30 degrees above the horizontal and a speed of 30 m/s. Ideally (no air r
marusya05 [52]

As we know that here no air resistance while ball is moving in air

So here we will say that

initial total energy = final total energy

KE_i + U_i = KE_f + U_f

here we know that

Ui = U_f = 0 (as it will be on ground at initial and final position)

so we will say

KE_i = KE_f

since mass is always conserved

so we will say that final speed of the ball must be equal to the initial speed of the ball

so we have

v_f = v_i = 30 m/s

6 0
3 years ago
Read 2 more answers
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