How would I label the y axis and fill it out and answer questions at the bottom I need answers please and thanks

A physical therapy exercise has a person shaking a 5.00 kg weight up and down rapidly. if the barbell is moving at 4.50 m/s, wha

Ivanshal [37]

The magnitude of the force required to stop the weight in 0.333 seconds is 67.6 N.

<h3>Magnitude of required force to stop the weight</h3>

The magnitude of the force required to stop the weight in 0.333 seconds is calculated by applying Newton's second law of motion as shown below;

F = ma

F = m(v/t)

F = (mv)/t

F = (5 x 4.5)/0.333

F = 67.6 N

Thus, the magnitude of the force required to stop the weight in 0.333 seconds is 67.6 N.

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7 0

2 years ago

If a statue is made out of wood, which of these words correctly describes the statue?

bonufazy [111]

Answer:

Od- Wooden

Explanation:

It would not make sense if it was non-wood because that make it no a wood base product, OC is not right because its not a a plant that produces wood as its structural tissue and thus has a hard stem. An OA justT o take or get a supply of wood. so its Od

5 0

3 years ago

(Please help 25 points)

Maksim231197 [3]

The potential energy (P.E) of X at r is less than P.E at s.

The total energy (T.E) of Y is less than total energy (T.E) of X.

The PE of Y at v is greater than the PE of Z at c.

The speed of Y at i is .greater than that at v.

The kinetic energy (KE) of z at u is less than that at n.

The PE of Y at s is less than the PE of X at c.

The PE of X at c is less than the PE of Z at c.

The potential energy (P.E) of X at r is less than P.E at s due to greater displacement at s.

The total energy (T.E) of Y is less than total energy (T.E) of X because X has greater displacement from the planet.

The PE of Y at v is greater than the PE of Z at c due to greater displacement at v.

<h3>Speed of Y at i is .... that at u</h3>

The speed of Y at i is .greater than that at v because i is closer to the planet than v.

The kinetic energy (KE) of z at u is less than that at n because n is closer to the planet and will have greater velocity.

The PE of Y at s is less than the PE of X at c, because position c has greater displacement.

The TE of Z is greater than the TE of X due to greater displacement of Z from the planet.

The PE of X at c is less than the PE of Z at c due to greater displacement of Z from c.

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3 0

2 years ago

A solenoid inductor has an emf of 0.80 V when the current through it changes at the rate 10.0 A/s. A steady current of 0.20 A pr

barxatty [35]

Answer:

The number of turns of the inductor is 2000 turns.

Explanation:

Given;

emf of the inductor, E = 0.8 V

the rate of change of current with time, dI/dt = 10 A/s

steady current in the solenoid, I = 0.2 A

flux per turn, Ф = 8.0 μWb per

Determine the inductance of the solenoid, L

E = L(dI/dt)

L = E / (dI/dt)

L = 0.8 / (10)

L = 0.08 H

The inductance of the solenoid is given by;

$L = \frac{\mu_o N^2 A}{l}$

Also, the magnetic field of the solenoid is given by;

$B = \frac{\mu_o NI}{l}$

I is 0.2 A

$B = \frac{\mu_oN(0.2)}{l} = \frac{0.2\mu_o N}{l}$

$\frac{B}{0.2 } = \frac{\mu_o N}{l}$

$L = \frac{\mu_o N^2 A}{l} \\\\L = \frac{\mu_o N }{l} (NA)\\\\L = \frac{B}{0.2} (NA)\\\\L = \frac{BA}{0.2} (N)$

But Ф = BA

$L = \frac{\phi N}{0.2} \\\\\phi N = 0.2 L\\\\N = \frac{0.2 L}{\phi} \\\\N = \frac{0.2 *0.08}{8*10^{-6}}\\\\N = 2000 \ turns$

Therefore, the number of turns of the inductor is 2000 turns.

5 0

4 years ago

A 2.2 kg box is sliding along a frictionless horizontal surface with a speed of 1.8 m/s when it encounters a spring. (a) Determi

iogann1982 [59]

Answer:

a) $k = 2851.2\,\frac{N}{m}$ , b) $v = 0.54\,\frac{m}{s}$

Explanation:

a) According to the Principle of Energy Conservation, the kinetic energy of the box is transformed into elastic potential energy.

$\frac{1}{2}\cdot (2.2\,kg)\cdot (1.8\,\frac{m}{s} )^{2} = \frac{1}{2}\cdot k \cdot (0.05\,m)^{2}$

The spring constant is:

$k = 2851.2\,\frac{N}{m}$

b) The initial speed needed to compress the spring by 1.5 centimeters is:

$\frac{1}{2}\cdot (2.2\,kg)\cdot v^{2} = \frac{1}{2}\cdot (2851.2\,\frac{N}{m} )\cdot (0.015\,m)^{2}$

$v = 0.54\,\frac{m}{s}$

5 0

4 years ago