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Katen [24]
4 years ago
14

How would I label the y axis and fill it out and answer questions at the bottom I need answers please and thanks

Physics
1 answer:
yKpoI14uk [10]4 years ago
7 0

you must write the temprature of the copper sulfate solution on the on the y axis

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When magma flows on the surface on the surface, it is already called lava<br><br>TRUE OR FALSE​
castortr0y [4]

Answer:

True

Explanation:

I guess you made a mistake on question.

but I understood what you wanted to say.

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3 years ago
A car engine has power than a horse because a car engine does the same amount of work in time. Yasmin and Raj each had 10 boxes
labwork [276]

Answer:

A car engine has more power than a horse because a car engine does the same amount of work in time. Yasmin and Raj each had 10 boxes of equal weight to stack next to each other on the same shelf, at the same height and in the same arrangement. Yasmin completed the task in 2 minutes, while Raj took 3 minutes to stack his boxes. Raj applied less power than Yasmin because his stacking took more time to do the same amount of work.

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4 0
3 years ago
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Consider a positive charge Q and a point B twice as far away from Q as point A. What is the ratio of the electric field strength
Vikentia [17]

Answer:

\frac{E_{A}}{E_{B}}=4

Explanation:

The electric field is defined as the electric force per unit of charge, this is:

E=\frac{F}{q}.

The electric force can be obtained through Coulomb's law, which states that the electric force between to electrically charged particles is inversely proportional to the square of the distance between them and directly proportional to the product of their charges. The electric force can be expressed as

F=\frac{kQq}{r^{2}}.

By substitution we get that

E=\frac{kQq}{qr^{2}}\\\\E=\frac{kQ}{r^{2}}

Now, letting E_{A} be the electric field at point A, letting E_{B} be the electric field at point B, and letting R be the distance from the charge to A:

E_{A}=\frac{kQ}{R^{2}}\\\\E_{B}=\frac{kQ}{(2R)^{2}}.

The ration of the electric fields is

\frac{E_{A}}{E_{B}}=\frac{\frac{kQ}{R^{2}}}{\frac{kQ}{(2R)^{2}}}\\\\\frac{E_{A}}{E_{B}}=\frac{\frac{1}{R^{2}}}{\frac{1}{(2R)^{2}}}\\\\\frac{E_{A}}{E_{B}}=\frac{\frac{1}{R^{2}}}{\frac{1}{(4)R^{2}}}\\\\\\\frac{E_{A}}{E_{B}}=\frac{1}{\frac{1}{(4)}}\\\\\frac{E_{A}}{E_{B}}=4

This means that at half the distance, the electric field is four times stronger.

4 0
3 years ago
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Arturiano [62]

Answer:

Explanation:

While traveling through space, asteroids sometimes collide with each other and break up into smaller fragments. Comets shed dust as they roam the solar system. These 'break ups' result in numerous small particles and fragments, called meteoroids, which orbit the sun. ... Thus a meteor, or shooting star, is formed.

7 0
3 years ago
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I think it's Barium sulfate, the soild and percipitate
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3 years ago
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