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3 years ago

8

An automobile with a mass of 1165 kg accelerates at a rate of 5 m/s² in the forward direction. What is the net force acting on t

he automobile? N

1 answer:

Natalka [10]3 years ago

6 0

Ignore the displacement formula

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During the spin cycle of your clothes washer, the tub rotates at a steady angular velocity of 33.5 rad/s. Find the angular displ

zavuch27 [327]

Answer: angular displacement in rad = 3038.45 rad

angular displacement in rev = 483.589 rev

Explanation: mathematically

Angular velocity = angular displacement / time taken.

Angular velocity = 33.5 rad/s, time taken = 90.7s

33.5 = angular displacement /90.7

Angular displacement = 33.5 * 90.7 = 3038.45 rad

But 1 rev =2π

Hence 3038.45 rad to rev is

3038.45/2π = 483.599 rev

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3 years ago

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Ksenya-84 [330]

There is no gravity

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Object a has a mass of 20 g

Anarel [89]

And.. where is the rest of the question?

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2 years ago

A race car has a centripetal acceleration of 15.625 m/s2 as it goes around a curve. If the curve is a circle with radius 40 m, w

myrzilka [38]

The centripetal acceleration is given by
$a_c = \frac{v^2}{r}$
where v is the tangential speed and r the radius of the circular orbit.

For the car in this problem, $a_c = 15.625 m/s^2$ and r=40 m, so we can re-arrange the previous equation to find the velocity of the car:
$v= \sqrt{a_c r}= \sqrt{(15.625 m/s^2)(40 m)}=25 m/s$

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2 years ago

Solve 1 for x if a=-9.8, v=2.7, and t= 35

aliina [53]

Explanation:

x=VT+at²/2

x=2.7x35+9.8x(35)²/2

x=6097

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3 years ago

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