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marta [7]
3 years ago
8

Matthew launches a ball at 34 meters/sec from a 28 meter tall platform. The function of the ball's height (h) at time (t) second

s after launch is h(t) = -2t^2+34t+28. Determine how long it will take for the ball to be at its original height.
Mathematics
1 answer:
Alex17521 [72]3 years ago
5 0

Answer:

17 seconds

Step-by-step explanation:

h(t) represents height, we want to know when the ball will return to a height of 28 feet.  So our equation is..

28 = -2t² + 34t + 28

Now solve for t...

0 = -2t² + 34t         (subtract 28 from both sides)

0 = t² - 17t             (divide both sides by -2)

0 = t(t - 17)          (factor out a t)

So

t = 0

or

t - 17 = 0

  t = 17          

0 seconds is the initial height.  At 17 seconds, the ball will return to that height

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8 and 10 are the integers
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What is the common difference, d, in the arithmetic sequence defined by the formula below? an=2n+1
marishachu [46]
<h3><u>Answer:</u></h3>

  • d = 2

<h3><u>Solution:</u></h3>

We are given that the arithmetic progression is defined by :

➝ 2n + 1

<em>Therefore, </em>

  • <u>For </u><u>first </u><u>term</u>

➙ n = 1

➝ 2 × 1 + 1

➝ 2 + 1

➝ 3

  • <u>For </u><u>second </u><u>term</u>

➙ n = 2

➝ 2 × 2 + 1

➝ 4 + 1

➝ 5

  • <u>Common </u><u>difference</u>

➙ 2nd term - 1st term

➝ 5 - 3

➝ 2

<h3><u>More </u><u>information</u><u>:</u></h3>

  • The difference between the successive term and the preceding term is the difference of an arithmetic progression. It is always same for the same arithmetic progression.

5 0
2 years ago
1.) Determine the type of solutions for the function (Picture 1)
NNADVOKAT [17]

Answer:

1) 2 nonreal complex roots

2) 1 Real Solution

3) 16

4) Reflected, narrower by a factor of 2/5, slides right 4 units and slides up 6 (units)

Step-by-step explanation:

1) The graph does not intercept the x-axis, therefore, there are no real solutions at the point y = 0

We get;

y = a·x² + b·x + c

At y = 6, x = -2

Therefore;

6 = a·(-2)² - 2·b + c = 4·a - 2·b + c

6 = 4·a - 2·b + c...(1)

At y = 8, x = 0

8 = a·(0)² + b·0 + c

∴ c = 8...(2)

Similarly, we have;

At y = 8, x = -4

8 = a·(-4)² - 4·b + c = 16·a - 4·b + 8

16·a - 4·b = 0

∴ b = 16·a/4 = 4·a

b = 4·a...(3)

From equation (1), (2) and (3), we have;

6 = 4·a - 2·b + c

∴ 6 = b - 2·b + 8 = -b + 8

6 - 8 = -b

∴ -b = -2

b = 2

b = 4·a

∴ a = b/4 = 2/4 = 1/2

The equation is therefor;

y = (1/2)·x² + 2·x + 8

Solving we get;

x = (-2 ± √(2² - 4 × (1/2) × 8))/(2 × (1/2))

x =( -2 ± √(-12))/1 = -2 ± √(-12)

Therefore, we have;

2 nonreal complex roots

2) Give that the graph of the function touches the x-axis once, we have;

1 Real Solution

3) The given function is f(x) = 2·x² + 8·x + 6

The general form of the quadratic function is f(x) = a·x² + b·x + c

Comparing, we have;

a = 2, b = 8, c = 6

The discriminant of the function, D = b² - 4·a·c, therefore, for the function, we have;

D = 8² - 4 × 2 × 6 = 16

The discriminant of the function, D = 16

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A vertical translation is given by the following equation;

y = f(x) + b

A horizontal to the right by 'a' translation is given by an equation of the form; y = f(x - a)

A vertical reflection is given by an equation of the form; y = -f(x) = -x²

A narrowing is given by an equation of the form; y = b·f(x), where b < 1

Therefore, the transformations of g(x) from the parent function are;

g(x) is a reflection of the parent function, with the graph of g(x) being narrower by 2/5 than the graph of the parent function. The graph of g(x) is shifted right by 4 units and is then slides up by 6 units.

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If a number increases from 47 to 70.5 what is the rate of increase?
FrozenT [24]
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Oksanka [162]

The maturity value of a loan of $2500 at the simple interest rate of 4.3% that is needed to be repaid in 8 months is $2607.50.

<h3>What is simple interest?</h3>

Simple interest is a method of calculating interest on an amount for n period of time with a rate of interest of r. It is calculated with the help of the formula,

SI = \dfrac{P\times R\times T}{100}

where SI is the simple interest, P is the principal amount, R is the rate of interest, and T is the time period.

As it is given the principal amount of the loan is $2500, while the interest rate is 4.3%, therefore, after a period the interest on the loan will be,

SI = \dfrac{P\times R\times T}{100}\\\\SI = \dfrac{2500 \times 4.3 \times 1}{100}\\\\SI =107.5

Thus, the interest amount on the loan of $2500, is $107.5.

Now, in order to find the value of the loan we need to add the interest and the principal amount of the loan together. Therefore, the value of the loan can be written as,

The value of the loan = Principal Amount + Interest rate

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Hence, the maturity value of a loan of $2500 at the simple interest rate of 4.3% that is needed to be repaid in 8 months is $2607.50.

Learn more about Simple Interest:

brainly.com/question/2793278

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