Answer:
Step-by-step explanation:
Hello!
The variable of interest is:
X: number of daily text messages a high school girl sends.
This variable has a population standard deviation of 20 text messages.
A sample of 50 high school girls is taken.
The is no information about the variable distribution, but since the sample is large enough, n ≥ 30, you can apply the Central Limit Theorem and approximate the distribution of the sample mean to normal:
X[bar]≈N(μ;δ²/n)
This way you can use an approximation of the standard normal to calculate the asked probabilities of the sample mean of daily text messages of high school girls:
Z=(X[bar]-μ)/(δ/√n)≈ N(0;1)
a.
P(X[bar]<95) = P(Z<(95-100)/(20/√50))= P(Z<-1.77)= 0.03836
b.
P(95≤X[bar]≤105)= P(X[bar]≤105)-P(X[bar]≤95)
P(Z≤(105-100)/(20/√50))-P(Z≤(95-100)/(20/√50))= P(Z≤1.77)-P(Z≤-1.77)= 0.96164-0.03836= 0.92328
I hope you have a SUPER day!
Answer: The integer is +6
Step-by-step explanation:
This is because it say TWICE so double that and 6 added twice is 12.
SO the integer is 6 not -6 because they would cancel out and you would end up with a 0
Hope that helps
1) |−11| = 11, therefore Peter is at a distance of 11 feet
2) Jimmy, because each of the two points is fraction 5 over 8 unit away from 0
3) 36 + 28=64 4x4=36+4x7=28 36+28=64
7+9=16 4x16=64
8 peaches. 8 peaches because if effie ate 4 peaches, or half of the bag, you would have to multiply 4 by 2 to get the answer of 8 peaches. mark brainliest please!
