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Sliva [168]
3 years ago
14

Submarine a is position at -1100 feet in relation to sea level. Submarine be is position at -800 feet in relation to sea level.

Each submarine needs to be 200 feet below sea level in 30 minutes. Which compares the speed at which each submarine needs to travel?
Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
7 0

Answer:

<u>Submarine A needs to travel at 30 feet per minute and the Submarine B at a lower speed, 20 feet per minute. </u>

Step-by-step explanation:

This is the information given to solve the question:

Submarine A position = - 1,100 feet

Submarine B position = - 800 feet

New position for Submarine A and B = - 200 feet

Duration of the travel = 30 minutes

Distance that Submarine A need to travel = - 200 + 1,100 = 900 feet

Distance that Submarine B need to travel = - 200 + 800 = 600 feet

For calculating the speed, we do this new calculation:

Speed Submarine A = Distance that Submarine A need to travel/Duration of the travel

Speed Submarine A = 900 feet/30 minutes

Speed Submarine A = 30 feet/minute (Dividing by 30)

Speed Submarine B = 600 feet/30 minutes

Speed Submarine B = 20 feet/minute (Dividing by 30)

<u>Submarine A needs to travel at 30 feet per minute and the Submarine B at a lower speed, 20 feet per minute. </u>

dimulka [17.4K]3 years ago
3 0

Answer:

A is correct answer

Step-by-step explanation:

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