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LekaFEV [45]
3 years ago
12

When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constan

t force acts upon an object with mass 4kg, the acceleration of the object is 15/ms2. If the same force acts upon another object whose mass is
10kg, what is this object's acceleration?
Mathematics
1 answer:
vitfil [10]3 years ago
4 0

Answer:

a = 6m/s^2

Step-by-step explanation:

Given

When mass = 4kg; Acceleration = 15m/s²

Required

Determine the acceleration when mass = 10kg, provided force is constant;

Represent mass with m and acceleration with a

The question says there's an inverse variation between acceleration and mass; This is represented as thus;

a\ \alpha\ \frac{1}{m}

Convert variation to equality

a = \frac{F}{m}; Where F is the constant of variation (Force)

Make F the subject of formula;

F = ma

When mass = 4kg; Acceleration = 15m/s²

F = 4 * 15

F = 60N

When mass = 10kg; Substitute 60 for Force

F = ma

60 = 10 * a

60 = 10a

Divide both sides by 10

\frac{60}{10} = \frac{10a}{10}

a = 6m/s^2

<em>Hence, the acceleration is </em>a = 6m/s^2<em />

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viktelen [127]

Answer:

87.5(the first one)

Step-by-step explanation:

first simplify 4 to the 5th power(20) and multiply by 4 to the -7th(-35) and you will get -700 divide that by 4 to the -2nd(-8) and you will get 87.5

6 0
3 years ago
Read 2 more answers
Eight times the sum of 9 and some number is 192.​
vovikov84 [41]

Answer:

15

Step-by-step explanation:

To solve this, divide 192 by 8:

192/9 = 24

Subtract 9 from 24:

24 - 9 = 15

Therefore, 8 times the sum of 9 and 15 is 192

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You always need some time to get up after the alarm has rung. You get up from 10 to 20 minutes later, with any time in that inte
Mama L [17]

Answer:

a) P(x<5)=0.

b) E(X)=15.

c) P(8<x<13)=0.3.

d) P=0.216.

e) P=1.

Step-by-step explanation:

We have the function:

f(x)=\left \{ {{\frac{1}{10},\, \, \, 10\leq x\leq 20 } \atop {0, \, \, \, \, \, \,  otherwise }} \right.

a)  We calculate  the probability that you need less than 5 minutes to get up:

P(x

Therefore, the probability is P(x<5)=0.

b) It takes us between 10 and 20 minutes to get up. The expected value is to get up in 15 minutes.

E(X)=15.

c) We calculate  the probability that you will need between 8 and 13 minutes:

P(8\leq x\leq 13)=P(10\leqx\leq 13)\\\\P(8\leq x\leq 13)=\int_{10}^{13} f(x)\, dx\\\\P(8\leq x\leq 13)=\int_{10}^{13} \frac{1}{10} \, dx\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot [x]_{10}^{13}\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot (13-10)\\\\P(8\leq x\leq 13)=\frac{3}{10}\\\\P(8\leq x\leq 13)=0.3

Therefore, the probability is P(8<x<13)=0.3.

d)  We calculate the probability that you will be late to each of the 9:30am classes next week:

P(x>14)=\int_{14}^{20} f(x)\, dx\\\\P(x>14)=\int_{14}^{20} \frac{1}{10} \, dx\\\\P(x>14)=\frac{1}{10} [x]_{14}^{20}\\\\P(x>14)=\frac{6}{10}\\\\P(x>14)=0.6

You have 9:30am classes three times a week.  So, we get:

P=0.6^3=0.216

Therefore, the probability is P=0.216.

e)  We calculate the probability that you are late to at least one 9am class next week:

P(x>9.5)=\int_{10}^{20} f(x)\, dx\\\\P(x>9.5)=\int_{10}^{20} \frac{1}{10} \, dx\\\\P(x>9.5)=\frac{1}{10} [x]_{10}^{20}\\\\P(x>9.5)=1

Therefore, the probability is P=1.

3 0
3 years ago
A boy purchased(bought) a party length sandwich 59 in long. He wants to cut it into three pieces so that the middle piece is 6in
Leviafan [203]
Ok so let's start with what we know- the shortest piece is 8 inches so there's one length... then the middle piece is 6 inches longer than the shortest (6+ 8) so the middle piece would be 14 inches long. To find the last piece we can add up the other two pieces we know (14+8) which would be 22 and subtract that from how long the whole sandwich is (59-22) which would be 37 inches long. So in the end he shortest piece would be 8 inches, the middle 14 inches and the longest 37 inches.
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Please solve with explanation
Olin [163]

Answer:

See the files.

Step-by-step explanation

6 0
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