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svetlana [45]
3 years ago
5

#8 can anyone help? I need help solving this and showing the work

Mathematics
2 answers:
Schach [20]3 years ago
6 0
Hope this helps you...

tamaranim1 [39]3 years ago
3 0
Use distance formula
=√(3-3)^2 +(-4-4)^2
=√64
=8
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(+1)+(+4) =
marishachu [46]

Answer:

5

8

3

15

8

16

6

6

10

3

3

9

14

6

9

9

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Ben earns an annual income of $12,800 a year. The income tax he has to pay is 15%. What is the amount of income tax in dollars a
Alex17521 [72]
<h2>D</h2>

Find 15% of 12,800,

\frac{15}{100} ×\frac{12,800}{1}

= 1,920

8 0
2 years ago
What is -5.8+(-2.5)
Scilla [17]

-5.8 + (-2.5) = -8.3

since both the number are negative you simply add the numbers and use the negative sign.

5 0
3 years ago
Please Help!<br><br> What is a cubic polynomial function in standard form with zeros –5, –1, and –5?
yan [13]
FIRST. find the factors:
X=-5 --> (X + 5) = 0
x = 1--> (X - 1) = 0
x =3 --> (x - 3) = 0
3
NEXT, multiply all the factors:
(x + 5) (x - 1) (x - 3) = 0
-> X3 + x2 - 17x +15 = 0
-> f(x) = x3 + x2 - 17x +15 or
y=x3 + x2
17x + 15
8 0
1 year ago
How do you do series with an n
SOVA2 [1]
The problem can be solved step by step, if we know certain basic rules of summation.  Following rules assume summation limits are identical.
\sum{a+b}=\sum{a}+\sum{b}
\sum{kx}=k\sum{x}
\sum_{r=1}^n{1}=n
\sum_{r=1}^n{r}=n(n+1)/2

Armed with the above rules, we can split up the summation into simple terms:
\sum_{r=1}^n{40r-21n+8}=n
=40\sum_{r=1}^n{r}-21n\sum_{r=1}^n{1}+8\sum_{r=1}^n{1}
=40\frac{n(n+1)}{2}-21n^2+8n
=20n(n+1)-21n^2+8n
=28n-n^2

=> (a) f(x)=28n-n^2
=> f'(x)=28-2n 
=> at f'(x)=0 => x=14
Since f''(x)=-2 <0  therefore f(14) is a maximum
(b) f(x) is a maximum when n=14

(c) the maximum value of f(x) is f(14)=196
4 0
2 years ago
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