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4 years ago

#8 can anyone help? I need help solving this and showing the work

Mathematics

2 answers:

Schach [20]4 years ago

6 0

Hope this helps you...

tamaranim1 [39]4 years ago

3 0

Use distance formula
=√(3-3)^2 +(-4-4)^2
=√64
=8

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Find the point (,) on the curve =8 that is closest to the point (3,0). [To do this, first find the distance function between (,)

ELEN [110]

Question:

Find the point (,) on the curve $y = \sqrt x$ that is closest to the point (3,0).

[To do this, first find the distance function between (,) and (3,0) and minimize it.]

Answer:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

Step-by-step explanation:

$y = \sqrt x$ can be represented as: $(x,y)$

Substitute $\sqrt x$ for $y$

$(x,y) = (x,\sqrt x)$

So, next:

Calculate the distance between $(x,\sqrt x)$ and $(3,0)$

Distance is calculated as:

$d = \sqrt{(x_1-x_2)^2 + (y_1 - y_2)^2}$

So:

$d = \sqrt{(x-3)^2 + (\sqrt x - 0)^2}$

$d = \sqrt{(x-3)^2 + (\sqrt x)^2}$

Evaluate all exponents

$d = \sqrt{x^2 - 6x +9 + x}$

Rewrite as:

$d = \sqrt{x^2 + x- 6x +9 }$

$d = \sqrt{x^2 - 5x +9 }$

Differentiate using chain rule:

Let

$u = x^2 - 5x +9$

$\frac{du}{dx} = 2x - 5$

So:

$d = \sqrt u$

$d = u^\frac{1}{2}$

$\frac{dd}{du} = \frac{1}{2}u^{-\frac{1}{2}}$

Chain Rule:

$d' = \frac{du}{dx} * \frac{dd}{du}$

$d' = (2x-5) * \frac{1}{2}u^{-\frac{1}{2}}$

$d' = (2x - 5) * \frac{1}{2u^{\frac{1}{2}}}$

$d' = \frac{2x - 5}{2\sqrt u}$

Substitute: $u = x^2 - 5x +9$

$d' = \frac{2x - 5}{2\sqrt{x^2 - 5x + 9}}$

Next, is to minimize (by equating d' to 0)

$\frac{2x - 5}{2\sqrt{x^2 - 5x + 9}} = 0$

Cross Multiply

$2x - 5 = 0$

Solve for x

$2x =5$

$x = \frac{5}{2}$

Substitute $x = \frac{5}{2}$ in $y = \sqrt x$

$y = \sqrt{\frac{5}{2}}$

Split

$y = \frac{\sqrt 5}{\sqrt 2}$

Rationalize

$y = \frac{\sqrt 5}{\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$y = \frac{\sqrt {10}}{\sqrt 4}$

$y = \frac{\sqrt {10}}{2}$

Hence:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

3 0

3 years ago

Determine the intercepts of the line. x-intercept: ( , ) y-intercept: ( , )

olga2289 [7]

Answer:

y-intercept = 275

x-intercept = 125

Step-by-step explanation:

The y-intercept is the point on your line where x=0. On this line, the y-intercept is the point (0,275) (x,y)

The x-intercept is the point on your line where y=0. On this line, the x-intercept is the point (125,0) (x,y)

6 0

3 years ago

Plzz help asap.......

SSSSS [86.1K]

Answer:

29.78 feet

Step-by-step explanation:

4 0

3 years ago

8=1/3(a+5) Please help and thank you :)

s344n2d4d5 [400]

Answer:

a=19

Step-by-step explanation:

First we have to distribute the parenthesis; multiply (a+5) by 1/3

8=1/3*a+1/3*5

Now we just solve the equation regularly

8=1/3a+5/3

8-5/3=1/3a

6 1/3=1/3a

a=19

6 0

3 years ago

Read 2 more answers

Please help i have 2 questions thank you very much.

Rudik [331]

Hello!

Question 1
We first have to convert everything to yards since the concrete is charged by the cubic yards

15 feet = 5 yards
15 feet = 5 yards
3 inches = 0.08333

Multiply these to find the volume

5 * 5 * 0.08333 = 2.08325

Multiply this by the cost

2.08325 * 46 = 95.83

The answer is C) $95.83
------------------------------------------------------------------------------------------------------
Question 2

You have to find the volume of the first pyramid

The equation we use is $V = \frac{lwh}{3}$

V is volume
l is length
w is width
h is height

Put in the values we know

$V = \frac{16 * 16 * 28}{3}$

Multiply

$V = \frac{7168}{3}$

Divide

V = 2389.3333

Now we use this to find the side length of the second pyramid

$2389.333 = \frac{lw * 112}{3}$

Multiply both sides by 3

7167.999 = lw * 112

Divide both sides by 112

63.9999 = lw

Since it is a square pyramid we know that sides are equal

63.999 = l^2

Take the square root of both sides

8 = l

The answer is B) 8in

Hope this helps!

8 0

3 years ago