Answer:
the answer is C. 20/27 cubic cm.
Step-by-step explanation:
V = LWH
length 5(1/3 cm)
width 2(1/3 cm)
height 2(1/3 cm)
V = (5/3 cm) (2/3 cm) (2/3 cm)
V = 20/27 cubic cm.
Actually, the correct volume formula is:
Sphere Volume = <span> 4/3 • <span>π <span>• r³
</span></span></span>Sphere Volume = <span> (4/3) * PI * (1.25)^3
</span>Sphere Volume = (4/3) * PI *
<span>
<span>
<span>
1.953125
</span>
</span>
</span>
Sphere Volume =
<span>
<span>
<span>
8.1812308687
</span>
</span>
</span>
cubic inches
Step-by-step explanation:
The question needs to be more specific. But assuming it is 0.5y/(4/9), I will solve it.
This would make it 4.5y/4 =y + 3/8
- Multiply 4 to both sides
4.5y = 4y + 12/8
- Subtract 4y to both sides
0.5y = 12/8
- Divide both sides by 0.5
y = 3
Now plug in to check.
0.5(3)/(4/9)=3+3/8
Both equals 3.375!
If this helped, please feel free to pick this answer as the brainliest! Thank you very much and have a wonderful day!
Answer:
Maximum area possible
f(max) = 3906,25 ft²
Dimensions:
a = 62,5 ft
w = 62,5 ft
Step-by-step explanation:
Perimeter of the rectangular fencing P = 250 feet
And sides of the rectangle a and w (width of rectangle)
Then
A = a*w
2a + 2w = 250 ⇒ a = (250 -2w)/ 2 ⇒ a = 125 - w
f(w) = (125 - w ) *w f(w) = 125w - w²
Taking derivatives both sides of the equation
f´(w) = 125 - 2w f´(w) = 0 125 - 2w = 0
w = 125/2
w = 62,5 ft ⇒ a = 125 - 62,5
a = 62,5 ft
f(max) = ( 62,5)²
f(max) = 3906,25 ft²
Answer: No, these results are not statistically significant because
p > 0.05
Step-by-step explanation:
The null hypothesis is
H0 : μ = 17
The alternative hypothesis is
H 1 : μ ≠ 17
where μ is the mean amount of cereal in each box.
The p value that he got is 0.1499. This is greater than alpha = 0.05 which is the given level of significance.
If the level of significance is lesser than the p value, we would accept the null hypothesis.
Therefore, the correct option is
No, these results are not statistically significant because p>0.05
